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boyakko [2]
3 years ago
10

The human body receives sensory information from its surroundings. The body knows when food is warm or cold and whether an objec

t is smooth or fuzzy. The body sends signals to other parts of the body, which then respond to the information. Which organ processes the sensory information the body receives?
(A)stomach

(B)brain

(C)heart

(D)skin
Chemistry
1 answer:
Rudiy273 years ago
8 0
The correct answer is Brain
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The d orbital in the most stable configuration for Cu would be one that has how many electrons
omeli [17]

The most stable configuration for Cu (copper) would be 1s2 2s2 2p6 3s2 3p6 4s2 3d9 for the noble gas configuration would be (Ar) 4s2 3d9.

3 0
3 years ago
How many moles of carbon dioxide are produced when 23.0 g of C3H2O3 is burned during the
Mars2501 [29]

Moles of Carbon dioxide : 0.75

<h3>Further explanation</h3>

Given

23 g C₃H₈O₃

Required

Moles of Carbon dioxide

Solution

Reaction

2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O

mol C₃H₈O₃ :

= mass : MW

= 23 g : 92,09382 g/mol

= 0.24975

From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :

= 3/1 x mol C₃H₈O₃

= 3/1 x 0.24975

= 0.74925≈0.750 mol

5 0
3 years ago
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio
Alja [10]

Answer:

Concentration of original solution = 1.66

Explanation:

We know that

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

We have given concentration of NaOH = 0.1678

Volume of NaOH = 19.88 mL = 0.01988 L

So moles of NaOH = volume x concentration of NaOH

= 0.01988\times 0.1678=0.00333mole

Moles of H_2SO_4 in 10 mL of diluted solution = 1/2 x moles of NaOH

= \frac{1}{2} x 0.00333 = 0.00166 mol

Moles of H_2SO_4 in 25 mL of original solution

= moles of H2SO4 in 250 mL of diluted solution

= \frac{250}{10} x 0.00166 = 0.0415 mol

Concentration of original solution = \frac{moles}{volume}

= \frac{0.0415}{0.025}=1.66

8 0
3 years ago
Enter your answer in the provided box. Find the pH of a buffer that consists of 0.34 M HBrO and 0.89 M KBrO (PK, of HBrO = 8.64)
11111nata11111 [884]

Answer : The  pH of buffer is 9.06.

Explanation : Given,

pK_a=8.64

Concentration of HBrO = 0.34 M

Concentration of KBrO = 0.89 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[KBrO]}{[HBrO]}

Now put all the given values in this expression, we get:

pH=8.64+\log (\frac{0.89}{0.34})

pH=9.06

Therefore, the pH of buffer is 9.06.

6 0
3 years ago
Halogens have ------ electron affinity
Fynjy0 [20]
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7 0
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