Answer:
Explanation:
a )
1.25 g MgO contains .754 g of Mg .Rest will be O
so oxide = 1.25 - .754 = 0.496 g
ratio of magnesium to oxide = .754/.496 = 1.52
b) 1.25 g of MgO contains .754 g of Mg
534 g of MgO contains .754 x 534 / 1.25 g = 322.11 g
D. Time
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Answer:
Keq = 5.33*10²⁶
Explanation:
Based on the standard reduction potential table:
E°(Fe2+/Fe) = -0.45 V
E°(Cu2+/Cu) = +0.34 V
Since the reduction potential of copper is greater than iron, the former acts as the cathode and the latter as anode.
The half reactions are:
Cathode (Reduction): 
Anode (Oxidation):
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Overall reaction: 
The Gibbs free energy change at 25 C is related to the standard emf (E°) of the cell as well as the equilibrium constant K as:

here:

R = 8.314 J/mol-K
T = 25 C = 25+273 = 298 K
n = number of electrons involved = 2
F = 96500 Coulomb/mol e-

Keq = 5.33*10²⁶