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Citrus2011 [14]
3 years ago
12

What is the mass of a cube measuring 3cm on each side that had a density of 8.1g/cm3?

Chemistry
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

48.6 g

Explanation:

Given data:

Length of one side = 3 cm

Density of cube = 8.1 g/cm³

Mass of cube = ?

Solution:

First of all we will calculate the volume of cube.

V = length × height × width

V = 3 cm × 3cm× 3cm

V = 27cm³

Now we will determine the mass by using density formula.

d = m/v

d = density

m = mass

v = volume

8.1 g/cm³ = m/ 27 cm³

m = 8.1 g/cm³ ×27 cm³

m = 48.6 g

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A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written betweenZn^{2+} (Positive ion)and F^{-} (Negative ion)

First Formula would be ZnF_{2}

Second empirical formula is between Zn^{2+}(Positive ion) and O^{2-}(Negative ion)

Second Formula would be Zn_{2}O_{2}

Note : When the subscript are same they get cancel out, so Zn_{2}O_{2} would be written as ZnO

Third empirical formula is between Ni^{4+}(Positive ion) and F^{-}(Negative ion)

Third Formula would be :NiF_{4}

Forth empirical formula is between Ni^{4+}(Positive ion)and O^{2-}(negative ion)

Forth Formula would be : Ni_{2}O_{4} or NiO_{2}

Note- The subscript will be simplified and the formula will be written as NiO_{2}.

The empirical formula of four binary ionic compounds are : ZnF_{2}, ZnO, NiF_{4},NiO_{2}


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