Answer:
ΔH₁₂ = -867.2 Kj
Explanation:
Find enthalpy for 3H₂ + O₃ => 3H₂O given ...
2H₂ + O₂ => 2H₂O ΔH₁ = -483.6 Kj
3O₂ => 2O₃ ΔH₂ = + 284.6 Kj
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3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O (multiply by 3 to cancel O₂)
6H₂ + 3O₂ => 6H₂O ΔH₁ = 3(-483.6 Kj) = -1450.6Kj
2O₃ => 3O₂ ΔH₂ = -284.6Kj (reverse rxn to cancel O₂)
_______________________________
6H₂ + 2O₃ => 6H₂O ΔH₁₂ = -1735.2 Kj (Net Reaction - not reduced)
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divide by 2 => target equation (Net Reaction - reduced)
3H₂ + O₃ => 3H₂O ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj
Answer:
13-b
Explanation:
because 13-b is close to a and 12
The mass number goes on top, and the atomic number goes on bottom.
Therefore, the answer is C:
40
K
19
Answer:
1. For a hot summer day, 35 degrees Celsius is most appropriate.
2. For room temperature, 20 degrees Celsius is most appropriate.
3. Aluminum's density is found by dividing mass by volume. 45 / 15 = 3 g/mL. The density is 3 g/mL.
4. Volume is found by multiplying length x width x height. 2cm x 5cm x 4cm equals 40 cm. We then divide the mass by volume to find density. 80 / 40 = 2 g/cm³. The density is 2 g/cm³.
