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Kay [80]
3 years ago
5

Bromine, a liquid at room temperature, has a boiling point of 58C and a melting point of -7.2C. Bromine can be classified as a

Chemistry
1 answer:
jarptica [38.1K]3 years ago
3 0

Bromine, a liquid at room temperature, has a boiling point of 58 degrees Celsius and a melting point of -7.2 degrees Celsius. Bromine can be classified as a pure substance. It is liquid at room temperature but evaporates very rapidly into a purple – brown choking gas.

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Write the formular of the compound formed when element D and oxygen react together​
miss Akunina [59]

Answer:

D oxide

Explanation:

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4 0
2 years ago
A solid cylinder having a diameter of 1.50 cm and a height of 5.15 cm has a mass of 95.56 g. Show the equations needed to calcul
Georgia [21]

Answer:

you can solve the rest of the equation. I only reduced it to that much to show you how to derive it

4 0
2 years ago
Noble gas notation for platinum
SOVA2 [1]

Pt

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4 0
3 years ago
13.0 g NaHSO4 is dissolved in water to make a 2.00 L solution what is the molarité
Sati [7]

Answer:

0.054 M

Explanation:

1 mol NaHSO4 -> 120 g

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8 0
3 years ago
Water (with density of 1000 kg/m3) with the mass flowrate of 10 kg/sec is flowing into an empty tank. The outlet volumetric flow
Montano1993 [528]

Explanation:

Apply the mass of balance as follows.

   Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank

         \frac{d}{dt}(\rho V) = 10 - \rho \times (0.01 h)

      \rho A_{c} \frac{dh}{dt} = 10 - (0.01) \rho h

   \frac{dh}{dt} + \frac{0.01 \rho h}{\rho A_{c}} = \frac{10}{\rho A_{c}}

          [/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] = \frac{10}{\rho A_{c}}

                       A_{c} = 0.01 m^{2}

              \frac{dh}{dt} + h = 1

                  \frac{dh}{dt} = 1 - h

               \frac{dh}{1 - h} = dt  

                \frac{ln(1 - h)}{-1} = t + C      

Given at t = 0 and V = 0  

                         A \times h = 0  

 or,                     h = 0

                 -ln(1 - h) = t + C

Initial condition is -ln(1) = 0 + C

                                C = 0  

                So,   -ln(1 - h) = t

or,                      t = ln (\frac{1}{1 - h})  ........... (1)

(a)    Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.

                    t = ln (\frac{1}{1 - h})  

                     t = ln (\frac{1}{1 - 0.6})  

                        = ln (\frac{1}{0.4})

                        = 0.916 seconds

(b)   As maximum height of water level in the tank is achieved at steady state that is, t = \infty.  

                    1 - h = exp (-t)

                    1 - h = 0  

                         h = 1

Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.

                 

8 0
3 years ago
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