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ahrayia [7]
4 years ago
12

Answer to AP chem question

Chemistry
1 answer:
steposvetlana [31]4 years ago
7 0

Answer:

C4H8

Explanation:

M(CF2) = M(C) + 2M(F) = 12.0 + 2*19.0 = 50.0 g/mol

M(unknown)/M(CF2) = 200.4 g/mol /50.0 g/mol = 4

So we need to take CF2 4 times.

C4H8

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Why are hydrogen, lithium, and sodium classified as reactive elements?
Sergeu [11.5K]
<span>The alkali metals and hydrogen are reactive because they have only one electron to give in order to complete their valence shell. It is easier to give that one electron so when given the opportunity they will. This means they will react with anything polar or willing to take an electron.</span>
4 0
4 years ago
28. How many formula units are found in 0.250 moles of potassium nitrate?
Soloha48 [4]

Answer:

\boxed {\boxed {\sf B. \ 1.5 *10^{23} \ formula \ units}}

Explanation:

1 mole of any substance contains the same number of particles. The particles can vary (atoms, molecules, formula units), but there are always 6.022*10²³ particles. In this case, the particles are formula units of potassium nitrate or KNO₃.

Let's create a ratio.

\frac {6.022*10^{23} \ formula \ units  \ KNO_3}{1 \ mol \ KNO_3}

Since we are trying to find the formula units in 0.250 moles, we multiply by that number.

0.250 \ mol \ KNO_3 *\frac {6.022*10^{23} \ formula \ units  \ KNO_3}{1 \ mol \ KNO_3}

The units of moles of potassium nitrate cancel.

0.250  *\frac {6.022*10^{23} \ formula \ units  \ KNO_3}{1 }

The denominator of 1 can be ignored, so we can make a simple multiplication problem.

0.250  *{6.022*10^{23} \ formula \ units  \ KNO_3}

1.5055 * 10^{23} \ formula \ units \ KNO_3

If we round to the nearest tenth, the 0 in the hundredth place tells us to leave the 5 in the tenth place.

1.5 *10^{23} \ formula \ units \ KNO_3

0.250 moles of potassium nitrate is approximately equal to 1.5*10²³ formula units of potassium nitrate and choice B is correct.

7 0
3 years ago
2. Convert 1500 milligrams to grams.​
Kisachek [45]

Answer: 1.5 grams.

Explanation:

7 0
3 years ago
Calculate the volume of 1 M NaOH needed to prepare 10.0 ml of a 0.10 M solution.
Mumz [18]
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
7 0
3 years ago
Oxygen and nitrogen are both gases at room temperature. Explain why oxygen has a greater force of attraction between its particl
rodikova [14]

Answer:

Explanation:

Oxygen molecules are formed as a result of covalent bonding between two atoms of oxygen. There is a sharing of two valence electrons so as to complete their respective octets. This is also similar to the formation of nitrogen molecules.

Oxygen has greater force of attraction because, the electronegativity of oxygen is the second strongest among the elements. Electronegativity deals with the relative tendency of an atom to attract electrons to itself. Therefore, the shared electrons are being greatly pulled by the two atoms of oxygen. The electronegativity of nitrogen is not as great as that of oxygen.

8 0
3 years ago
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