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bulgar [2K]
2 years ago
14

3. Briefly discuss the results of the TLC. Was there evidence of unreacted p-nitrobenzaldehyde in either product

Chemistry
1 answer:
Tems11 [23]2 years ago
4 0

TLC means Thin Layer Chromatography. It is a method that can best be described as "Affinity-Based" used in the separation of compounds that are in a mixture.

<h3>What is unreacted p-nitrobenzaldehyde?</h3>

Unreacted p-nitrobenzaldehyde is simply an organic aromatic compound that contains a nitro group para-substituted to an aldehyde. in this case, if it is unreacted, that means it is the same as before the chemical reation.

Note that the question is missing key information hence the general answer.

Learn more about TCL at:

brainly.com/question/10296715

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1) An unlabeled laboratory solution is found to contain a H+ ion concentration of 1 x 10-4
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Answer:

C) 1 x 10-10 M

Explanation:

To solve this question we must use the equation:

Kw = [H+] [OH-]

<em>Where Kw is the equilibrium dissociation of water = 1x10-14</em>

<em>[H+] is the molar concentration of hydronium ion = 1x10-4M</em>

<em>[OH-] is the molar concentration of hydroxyl ion</em>

<em />

Replacing:

1x10-14= 1x10-4 [OH-]

<em>[OH-] = 1x10-14 / 1x10-4M</em>

<em>[OH-] = 1x10-10 M</em>

Right option is:

<h3>C) 1 x 10-10 M </h3>

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Describe what is happening to the mass of water when sugar is dissolved in it.(5 sentences min) ​
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New questionWhat mass of calcium chloride (CaCl₂) would beproduced from the reaction of 125.9 g of hydrochloriacid (HCI) with ex
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Answer:

191.6 g of CaCl₂.

Explanation:

What is given?

Mass of HCl = 125.9 g.

Molar mass of CaCl₂ = 110.8 g/mol.

Molar mass of HCl = 36.4 g/mol.

Step-by-step solution:

First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O.

Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:

125.9\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=3.459\text{ moles HCl.}

Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:

3.459\text{ moles HCl}\cdot\frac{1\text{ mol CaCl}_2}{2\text{ moles HCl}}=1.729\text{ moles CaCl}_2.

The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:

1.729\text{ moles CaCl}_2\cdot\frac{110.8\text{ g CaCl}_2}{1\text{ mol CaCl}_2}=191.6\text{ g CaCl}_2.

The answer would be that we're producing a mass of 191.6 g of CaCl₂.

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