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oee [108]
2 years ago
10

All of the following use subjective scoring EXCEPT:

Physics
1 answer:
mamaluj [8]2 years ago
5 0

All of the following use subjective scoring EXCEPT Archery.

<h3>What is subjective scoring?</h3>

Subjective scoring is an important and powerful tool you can use to add assessment items that are not easily scored.

Archery is scored based on point values that is assigned to the rings made on the target. Others are not point scoring sports.

Thus, all of the following use subjective scoring EXCEPT Archery.

Learn more about subjective scoring.

brainly.com/question/11387559

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A neutral metal comb is held near an object with a negative charge. What happens to the comb?
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Answer:

Neutral comb is charged through induction.

Explanation:

The local charging of the comb is caused because of induction. The electron is pushed in the comb to the away side of the charged particle because of the negative charge which makes the close part positively charge.

Then after that when the observer move the comb away from the charge then the electron of the comb is redistributed.

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What are the methods of heat transfer? ​
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Which scientist first proposed physical laws to mathematically describe the effect of forces on the motions of bodies?
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2 years ago
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25
torisob [31]

Answer:

The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose  we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

We need to calculate the electric field

Using formula of electric field

E=\dfrac{V}{d}

Put the value into the formula

E=\dfrac{25.0}{1.50\times10^{-3}}

E=16666.66\ V/m

We need to calculate the charge density

Using formula of charge density

\sigma=E\times\epsilon_{0}

Put the value into the formula

\sigma=16666.66\times8.85\times10^{-12}

\sigma=1.474\times10^{-7}\ C/m^2

We need to calculate the capacitance

Using formula of capacitance

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}

C=4.484\times10^{-12}\ F

We need to calculate the charge

Using formula of charge

q=CV

Put the value into the formula

q=4.484\times10^{-12}\times25.0

q=112.1\times10^{-12}\ C

Hence, The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

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