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2 years ago

How does electricity affect objects that are not in contact with one another?

Physics

1 answer:

Elan Coil [88]2 years ago

5 0

Electrostatic forces are non-contact forces; they pull or push on objects without touching them

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Two children, Ferdinand and Isabella, are playing with a waterhose on a sunny summer day. Isabella is holding the hose in herhan

sweet [91]

Answer:

84.196%

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

$y_0=1\ m$

x = 10 m

t = Time taken

$v_0$ = 3.5 m/s (assumed, as it is not given)

$A_0$ = $\pi 1.5^2$

We have the equation

$y=y_0+ut+\dfrac{1}{2}gt^2\\\Rightarrow 0=y_0-\dfrac{1}{2}gt^2\\\Rightarrow t=\sqrt{\dfrac{2y_0}{g}}\\\Rightarrow t=\sqrt{\dfrac{2\times 1}{9.81}}\\\Rightarrow t=0.45152\ s$

$x=x_0+vt\\\Rightarrow 10=0+v0.45152\\\Rightarrow v=\dfrac{10}{0.45152}\\\Rightarrow v=22.14741\ m/s$

From continuity equation we have

$Av=A_0v_0\\\Rightarrow A=\dfrac{A_0v_0}{v}\\\Rightarrow A=\dfrac{\pi 1.5^2\times 3.5}{22.14741}\\\Rightarrow A=1.11706\ cm^2$

Fraction is given by

$f=\dfrac{A_0-A}{A_0}\times 100\\\Rightarrow f=\dfrac{\pi 1.5^2-1.11706}{\pi 1.5^2}\times 100\\\Rightarrow f=84.196\ \%$

The fraction is 84.196%

4 0

3 years ago

What is the gauge pressure at point A when spigot C is closed?

Nesterboy [21]

Given,

$\begin{gathered} l_1=0.2m \\ l_2=0.07m \\ h=0.47m \\ \rho=\frac{1g}{cm^3} \end{gathered}$

Atm

3 0

2 years ago

Calculate the potential energy of a 1200 kg boulder on a cliff 45 m above the ground.

Softa [21]

Explanation:

Given mass of the object is 1200kg and it's placed at a height of 45m above the ground. As we know that potential energy is ,

$\longrightarrow PE = mgh$

where,

m is the mass of the body .
g is acceleration due to gravity.
h is the height above the ground .

Substituting the respective values ,

$\longrightarrow P.E. = 1200kg * 10m/s^2* 45m$

Multiply ,

$\longrightarrow P.E. = 540000J$

Hence the potential energy is 540000J .

I hope this helps.

4 0

3 years ago

A kayaker moves 26 meters southward, then 18 meters

Svetllana [295]

Total distance: 56 meters. Magnitude and direction of displacement: 20 meters South.

Explanation:

The term distance refers to space between one point and other, or the total space a body or object covered while moving. In the case presented, this can be calculated by adding the partial distances given. This means the total distance is 56 meters as 26 meters + 18 meters + 12 meters = 56 meters.

On the other hand, displacement considers the distance from the initial position to the final position, and the direction of movement. This means partial distances should not be added but each movement should be considered according to the direction. The process is shown below:

-The first movement was 26 meters southward; this means by the end of this movement the distance between the initial position was 26 meters south.

- The second movement was 18 northward; this means the kayaker moved 18 meters towards the position. This changes the displacement to 8 meters South as 26 meters south - 18 meters north = 8 meters to the South.

-The last movement was 12 meters sound; this means the kayaker increased the distance from the original position 8 meters to the South + 12 meters to the South = 20 meters South (total displacement.)

8 0

3 years ago

Physicist ____ was found to have completely made up some of the data on which his astounding discoveries were made.

GaryK [48]

Answer:

Jan Hendrik Schön I believe

6 0

3 years ago