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2 years ago

How does electricity affect objects that are not in contact with one another?

Physics

1 answer:

Elan Coil [88]2 years ago

5 0

Electrostatic forces are non-contact forces; they pull or push on objects without touching them

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In a laboratory experiment, a computer determines that the time for a falling steel ball to travel the final 0.80 m before hitti

Roman55 [17]

Answer:

Vf = 9.622 m/s

Explanation:

Distance covered S=0.80m, Time t=0.087s and

g=9.81 m/s²

Required: Final velocity Vf when it hit the floor

Sol:

We have first find Vi so

Vi=Vit + 0.5 a t2

Vi =8.768m/s

Now Vf= Vi + at

Vf = 9.622 m/s

8 0

4 years ago

It is weigh-in time for the local under 85 kg rugby team. The bathroom scale used to assess eligibility can be described by Hook

Grace [21]

15 m/n is the answer

4 0

3 years ago

An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave

klemol [59]

Answer: $u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}$

Explanation:

Given

height of building h=3 m

Landing velocity of diver $v=8.90 m/s$ at an angle of $75^{\circ}$

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

$u\cos \theta =8.9\cos (75)$ ---- -----1

Considering Vertical motion

$v^2-u^2=2as$

here $v=8.9\sin (75)$

$u=u\sin \theta$

$s=3 m$

$a=9.8 m/s^2$

$(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3$

$u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}$

$u\sin \theta =3.886$ ----------------2

Divide 2 and 1 we get

$\tan \theta =\frac{3.886}{8.9\cos (75)}$

$\tan \theta =1.687$

$\theta =59.34^{\circ}$

Thus $u\cos (59.34)=8.9\cos (75)$

$u=4.51 m/s$

7 0

3 years ago

Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to

aev [14]

Answer:

D. Test a cell phone's reception in the exact same location under various atmospheric conditions

Explanation:

Components of an experiment:

Independent variable:

A manipulated variable, in an experiment or study, whose presence or degree incurs a change in the dependent variable.

Dependent variable:

A variable which is being studied in the experiment and is supposed to change with respect to the independent variable.

Control variable:

Control variable includes the variables which are of no concern in the experiment and must be constant so that they do not interfere with the results of the experiment. Change in control variable might affect the results of an experiment.

In Anna's experiment, the independent variable is the atmospheric conditions. The dependent variable is cell phone reception that will change according to the atmospheric conditions. All other things related to the experiment are control variables like cellphone, location of the cell phone. Both of these must stay constant to collect the best data.

Hence, the best option is D.

4 0

4 years ago

A chunk of metal has a volume of

Alla [95]

Answer:

7213.7kg/m³

Explanation:

Given parameters:

Volume of the metal chunk = 0.131m³

Mass of the metal chunk = 945kg

Unknown:

Density of the metal chunk = ?

Solution :

To solve this problem, density is the mass per unit volume. It is mathematically expressed as;

Density = $\frac{mass}{volume}$

So;

Density = $\frac{945}{0.131}$ = 7213.7kg/m³

5 0

3 years ago