Ask question

Ask question

All categories

3 years ago

15

You kick a soccer ball across a field the ball travels across the field and slowly comes to a stop. Since the ball slowly comes

to a stop what does this mean about the net force on the ball as it rolls across the field?

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

It slowly decreases and the friction acting on it slowing it down becomes the bigger net force, if that makes sense :)

Explanation:

You might be interested in

A boy throws a rock with an initial velocity of 2.15 m/s at 30.0° above the horizontal. If air resistance is negligible, how lon

vladimir1956 [14]

Answer:

t = 0.11 second

The time taken to reach the maximum height of the trajectory is 0.11 second

Explanation:

Taking the vertical component of the initial velocity;

Vy = Vsin∅

Initial velocity V = 2.15 m/s

Angle ∅ = 30°

Vy = 2.15sin30 = 2.15 × 0.5

Vy = 1.075 m/s

The height of the rock at time t during the flight is;

From the equation of motion;

h(t) = Vy×t - 0.5gt^2

g= acceleration due to gravity = 9.8m/s^2

Substituting the given values;

h(t) = 1.075t - 0.5(9.8)t^2

h(t) = 1.075t - 4.9t^2

The rock is at maximum height when dh/dt = 0;

dh(t)/dt = 1.075 - 9.8t = 0

1.075 - 9.8t = 0

9.8t = 1.075

t = 1.075/9.8

t = 0.109693877551 s

t = 0.11 second

The time taken to reach the maximum height of the trajectory is 0.11 second

4 0

4 years ago

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

Nat2105 [25]

Answer:

303

Explanation:

We are given that

Emf in coil 1, $E_1=3.13 V$

Emf induced in coil 2, $E_2=4.16 V$

Number of loops in coil 1, $N_1=228$

We have to find the number of loops in coil 2.

Rat of change of magnetic flux in a single loop is same.

Let $\phi_1$ and $\phi_2$ be the magnetic flux in coil 1 and coil 2.

$\frac{d\phi_1}{dt}=\frac{d\phi_2}{dt}$

$\frac{V_2}{V_1}=\frac{N_2}{N_1}$

Using the formula

$\frac{E_2}{E_1}=\frac{N_2}{N_1}$

$\frac{4.16}{3.13}=\frac{N_2}{228}$

$N_2=\frac{4.16}{3.13}\times 228$

$N_2=303$

Hence, the number of loops in coil 2=303

5 0

3 years ago

g A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 ra

Setler [38]

Answer:

The angular acceleration of the wheel is 15.21 rad/s².

Explanation:

Given that,

Time = 5 sec

Final angular velocity = 96.0 rad/s

Angular displacement = 28.0 rev = 175.84 rad

Let $\alpha$ be the angular acceleration

We need to calculate the angular acceleration

Using equation of motion

$\theta=\omega_{i} t+\dfrac{1}{2}\alpha t^2$

Put the value in the equation

$175.84=\omega_{i}\times 5+\dfrac{1}{2}\times\alpha\times(5)^2$

$175.84=\omega_{i}\times 5+12.5\alpha$ ......(I)

Again using equation of motion

$\omega_{f}=\omega_{i}+\alpha t$

Put the value in the equation

$96.0=\omega_{i}+\alpha \times 5$

On multiply by 5 in both sides

$480=\omega_{i}\times 5+\alpha\times 25$ ....(II)

On subtract equation (I) from equation (II)

$480-175.84=\alpha(25-5)$

$304.16=\alpha\times20$

$\alpha=\dfrac{304.16}{20}$

$\alpha=15.21\ rad/s^2$

Hence, The angular acceleration of the wheel is 15.21 rad/s².

5 0

3 years ago

Neglecting air resistance, when does a struck baseball accelerate downward at a rate of 9.8 m/s2?

olga2289 [7]

A baseball is accelerated downward at 9.8 m/s^2 when the only vertical force acting upon the baseball is gravity.

3 0

4 years ago

Read 2 more answers

David is investigating the properties of soil using the sample shown.

charle [14.2K]

Answer:

IT IS A BC ION KNOW WHY

Explanation:

5 0

2 years ago