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Fynjy0 [20]
3 years ago
15

During a baseball game, a batter hits a high .

Physics
1 answer:
Harman [31]3 years ago
7 0

Answer: Due that we don't know the initial speed after hitting the ball, we are going to accept that the ball goes up for half of the time and then falls during other half part, that is 3.0 seconds each. Then we know that ball's movement is ruled by the acceleration of gravity formula, as follows: H = Vi * T + 1/2 * g * T^2 V = Vi + g * T where: H is height, Vi initial speed, g gravity acceleration and T time When we only consider the second half of the trajectory, we have that initial speed at the top of that movement is zero, because ball goes up till top, where stops and starts to go down, so : H = 0 * 3 + 1/2 * 32 * 3^2 = 144 ft. So the height of the pop-up is 144 feet.

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What is true about the relationship between the kinetic energy of molecules in an object and the objects temperature?
vekshin1

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6 0
3 years ago
It takes 500 J of work to compress a spring 10 cm. What is the force constant of the spring? (b) When a 3.0 kg block is pushed a
NARA [144]

Answer:

Explanation:

a) Energy stored in spring = 1/2 k x² = .5 x k 0.1²

500 = 5 x 10⁻³ k ,

k = (500/5) x 10³ = 10⁵ N/m

b )

k = 4.5 x 10¹ = 45 N/m

Stored energy = 1/2 k x² = .5 x 45 x 8² x 10⁻⁴ =1440 x 10⁻⁴ J

This energy gets dissipated by friction .

work done by friction = μ mg d

d is the distance traveled under friction

so 1440 x 10⁻⁴ = μ x 3 x 9.8 x 2

μ = 245 x 10⁻⁴  or 0.00245 which appears to be very small. .

8 0
3 years ago
If a current is two amps and the resistance is 3 ohms, how much voltage was needed?
Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

V=RI

where

V is the voltage in the circuit

R is the resistance

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V=RI=(3 \Omega )(2 A)=6 V

7 0
2 years ago
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