The Protons determine the identity.
From what i can gather it looks like d
The answer is 62.026 g/mole
The amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
<h3>What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?</h3>
The heat required to melt a unit mass of ice is known as the latent heat of fusion.
The latent heat of fusion of ice of 1 kg= 334 kJ of heat
Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg
Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.
Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.
Learn more about latent heat of fusion at: brainly.com/question/87248
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-(1/8)Δ[H2S]/Δt = -(1/4)Δ[O2]/Δt
(1/8)Δ[H2S]/Δt = (1/4)Δ[O2]/Δt
(4)*((1/8)Δ[H2S]/Δt) = (4*)((1/4)Δ[O2]/Δt)
(1/2)Δ[H2S]/Δt = Δ[O2]/Δt
(1/2))*( -0.057 M/s) = Δ[O2]/Δt
Δ[O2]/Δt = -0.0285 M/s
