Answer:
Kc = [CH₄] / [H₂]²
Kp = [CH₄] / [H₂]² * (0.082*T)^-1
Explanation:
Equilibrium constant, Kc, is defined as the ratio of the concentrations of the products over the reactants. Also, each concentration of product of reactant is powered to its coefficient.
<em>Pure solids and liquids are not taken into account in an equilibrium</em>
Thus, for the reaction:
C(s)+ 2H₂(g) ⇌ CH₄(g)
Equilibrium constant is:
<h3>Kc = [CH₄] / [H₂]²</h3>
Now, using the formula:
Kp = Kc* (RT)^Δn
<em>Where R is gas constant (0.082atmL/molK), T is the temperature of the reaction and Δn is difference in coefficients of gas products - coefficients of gas reactants (1 - 2= -1)</em>
Replacing:
<h3>Kp = [CH₄] / [H₂]² * (0.082*T)^-1</h3>
<em />
Answer:
Crude oil is separated by fractional distillation. Crude oil is heated to vaporize the different hydrocarbons in a tank which is cool at the top and hot at the bottom. The vapours then rise and the different hydrocarbons condense at their specific boiling points, allowing them to be separated.
Lighter products, such as butane and other liquid petroleum gases (LPG), gasoline blending components, and naphtha, are recovered at the lowest temperatures. Mid-range products include jet fuel, kerosene, and distillates (such as home heating oil and diesel fuel).
Answer:
step 2
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Answer:
64g of Oxygen
Explanation:
Firstly, carbon and oxygen react to form CO2 as follows;
C + O2 => CO2
According to the equation, one mole of C reacts with one mole of O2 to give one mole of CO2
Since molar mass of C= 12g/mol, O= 16g/mol
One mole of (C) contains 12g
One mole of O2 contains 16(2) = 32g
Hence, If there are 24g of C, there would be 24 × 32 / 12
= 768/12
= 64g
Hence, there would be 64g of oxygen if there are 24g of Carbon
