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vladimir2022 [97]
3 years ago
9

How do I prepare for my general chemistry labs? How do I get good grades on labs?

Chemistry
2 answers:
Masja [62]3 years ago
8 0
Well you should study how different chemicals work, and make flashcards to carry around or make notes during class to study for later
Reika [66]3 years ago
6 0
You must make sure that you pay attention in class, follow directions, do all homework and assignments to the best of your abilities, listen to the teacher, ask for help when it is needed, now what is going on in that class, do not daze of and focus, understand the subject, and try your hardest.  You can get good grades by following all directions, completing it, putting lots of effort and detail into it, asking for help,and doing it the best that you possibly can.  Good Luck I'm sure you can do it!!
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based on your observation, you can infer that thermal energy transfers to/from objects with higher temperatures to/from objects
BlackZzzverrR [31]

Answer:

1. from      2. to

Explanation:

6 0
3 years ago
Calculate the enthalpy of the reaction below (∆Hrxn, in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g).
nalin [4]

The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

The bond energies data is given as follows:

BE  for C≡O  = 1072 kJ/mol

BE for Cl-Cl = 242 kJ/mol

BE for C-Cl = 328 kJ/mol

BE for C=O = 766 kJ/mol

The enthalpy change for the reaction is given as :

ΔHr×n = ∑H reactant bond - ∑H product bond

ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )

ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )

ΔHr×n = 1314 - 1422

ΔHr×n = - 108 kJ

Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

To learn more about enthalpy here

brainly.com/question/13981382

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7 0
1 year ago
Which color of light is diffracted at a greater angle from a diffraction grating, red or yellow?
Anit [1.1K]
The color of light that will be diffracted at a greater angle from a diffracting grating is THE YELLOW COLOR.
This is because, the degree of diffraction depend on the wavelength of light and light color with shorter wavelength are diffracted at a larger angle than those with longer wavelengths. The wavelength of the yellow color is much more smaller than that of the red color.
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3 years ago
Draw the R enantiomer of CFClBrI as a 3-D (wedge and dotted line) structure and as a Fischer projection (putting the I at the to
vazorg [7]
I don’t know This one is there a picture ?
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3 years ago
Why does water conduct electricity but only very poorly
e-lub [12.9K]

Answer:

actually pure water doesnt conduct electricity, any salts or impurities dissolved in water enable it to conduct electricity, When salts are dissolved in water, they separate into different electrically charged atoms called ions. Sodium chloride (NaCl), breaks up into positive Na ions and negative Cl ions.

5 0
3 years ago
Read 2 more answers
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