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2 years ago

Determine the quantity of charge on a plastic tube which has been rubbed with animal fur and gained 3.8 x 10^9 electrons

Physics

1 answer:

PSYCHO15rus [73]2 years ago

6 0

The quantity of charge carried by the plastic tube is -6.08 x 10^-10 C.

<h3>What are electrons?</h3>

Electrons are negatively charged particles that are found in the atom. The magnitude of charge carried by an electron is about -1.6 × 10^-19 C. We must note that the negative sign indicates that the electron is negatively charged.

The quantity of charge carried by the tube is obtained from;

q =ne

q = 3.8 x 10^9 × ( -1.6 × 10^-19 C)

q = -6.08 x 10^-10 C

Learn more about electrons:brainly.com/question/1255220

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Ple can someone help me to answer this question

ra1l [238]

The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

<h3 /><h3>A sketch of the uniform stick and the mass</h3>

The sketch of the uniform stick and the mass will be two based on the given statement.

<h3>when the uniform stick balances on knife at 10 cm from one end;</h3>

-------------------------------------------------------

↓ 10cm Δ (L - 10 cm) ↓

200g M

<h3>When the knife edge is moved 5 cm further</h3>

|---------------15 cm-----------------|

-----------------------------------------------------------------------

↓ 8.75 cm Δ (L - 15 cm) ↓

200g M

From the first diagram, apply principle of moment;

200(10) = M(L - 10) ------- (1)

From the second diagram, apply principle of moment;

200(8.75) = M(L - 15) ------- (2)

From equation (1); M = (2000) / (L - 10)

From equation (2); M = (1750) / (L - 15)

Solve (1) and (2);

(2000) / (L - 10) = (1750) / (L - 15)

1750(L - 10) = 2000(L - 15)

L - 10 = 2000/1750(L - 15)

L - 10 = 1.143(L - 15)

L - 10 = 1.143L - 17.14

17.14 - 10 = 1.143L - L

7.14 = 0.143L

L = 7.14/0.143

L = 50 cm

<h3>Mass of the uniform stick</h3>

M = (2000) / (50 - 10)

M = 50 g

Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.

Learn more about length of meter stick here: brainly.com/question/17225736

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8 0

2 years ago

Suppose the earth suddenly came to halt and ceased revolving around the sun. The gravitational force would then pull it directly

AleksAgata [21]

Answer:

613373.65233 m/s

Explanation:

M = Mass of Sun = $1.989\times 10^{30}\ kg$

m = Mass of Earth

v = Velocity of Earth

r = Distance between Earth and Sun = $147.12\times 10^{9}\ m$

$r_e$ = Radius of Earth = $6.371\times 10^6\ m$

$r_s$ = Radius of Sun = $695.51\times 10^6\ m$

In this system it is assumed that the potential and kinetic energies are conserved

$\dfrac{1}{2}Mv_2-\dfrac{GMm}{r_e+r_s}=0-\dfrac{GMm}{r}\\\Rightarrow v=\sqrt{2GM(\dfrac{1}{r_e+r_s}-\dfrac{1}{r})}\\\Rightarrow v=\sqrt{2\times 6.67\times 10^{-11}\times 1.989\times 10^{30}(\dfrac{1}{6.371\times 10^6+695.51\times 10^6}-\dfrac{1}{147.12\times 10^{9}})}\\\Rightarrow v=613373.65233\ m/s$

The velocity of Earth would be 613373.65233 m/s

3 0

3 years ago

An object is placed in front of a convex mirror with a radius of curvature of magnitude 10 cm. The mirror produces an image that

jek_recluse [69]

Answer:

u = - 20 cm

m = $\frac{1}{5}$

Given:

Radius of curvature, R = 10 cm

image distance, v = 4 cm

Solution:

Focal length of the convex mirror, f:

f = $\frac{R}{2} = \frac{10}{2} = 5 cm$

Using Lens' maker formula:

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

Substitute the given values in the above formula:

$\frac{1}{5} = \frac{1}{u} + \frac{1}{4}$

$\frac{1}{u} = \frac{1}{5} - \frac{1}{4}$

u = - 20 cm

where

u = object distance

Now, magnification is the ratio of image distance to the object distance:

magnification, m = $\frac{|v|}{|u|}$

magnification, m = $\frac{|4|}{|-20|}$

m = $\frac{4}{20}$

m = $\frac{1}{5}$

4 0

3 years ago

Jack and jill exercise in a 25.0-m-long swimming pool. jack swims nine lengths of the pool in 2 minutes and 19.5 seconds, while

Archy [21]

First of all, the average speed and average velocity would just have the same magnitude, so they are equal. Now, the average speed or average velocity is the total distance traveled divided by the elapsed time. For consistency of units, let's convert the time to seconds.

Time for Jack or Jill = 2 min(60s/1min) + 19.5 s = 139.5 seconds

Then, the average speed for each would be:
Average speed of Jack = 9(25 m)/139.5 s = 1.613 m/s
Average speed of Jill = 10(25 m)/139.5 s = 1.792 m/s

7 0

3 years ago

Read 2 more answers

Help please I do not understand

ahrayia [7]

What don’t you understand? If you haven’t uploaded anything

3 0

3 years ago