Answer:
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Explanation:
The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.
Given are
<em> mass of the student 73 kg</em>
<em> height of water glide 11.8 m</em>
<em> work done as -5.5*10³ J</em>
Have to find speed at which the student goes down the glide.
According to<em> Law of Conservation of energy</em>,
K.E =P.E+Work Done
mv²/2=mgh +W
Rearranging the above eqn for v
v = √2(gh+W/m)
Substituting values,
V = 12.48 m/s.
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Answer:
Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C
Explanation:
given,
surface charge (q) = 3.3 × 10⁻⁶ C
to calculate electric flux = ?
a) radius = 0.76 m
area of sphere = 4 π r²
electric flux = 
electric flux = 
flux = 0.373 × 10 ⁶ N m²/C
electric flux in the other two cases will also be same as electric flux is independent of area
so, Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C
The formula for orbital speed v is v=(G*Me/r)^1/2
Wher G= 6.67E-11, Me= 6E24, r= Re+h= 6.4E6+740000
putting values in the formula we get
v= 7486.7 m/s or v= 7.4867 km/s
