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never [62]
3 years ago
15

What is the correct answer for box c?

Chemistry
1 answer:
Inessa [10]3 years ago
3 0
The correct answer for box C is coefficient
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the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

5 0
3 years ago
In a laboratory experiment, john uses a message to seperate soil particles from water . Which technique separation which techniq
eimsori [14]
So visualize soil mixed with water. To separate it, you can use a sieve to filter the water.
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3 years ago
Through what process do all stars produce their energy?
Deffense [45]

nuclear fusion

Stars produce their energy through nuclear fusion. For most stars, this process is dominated by a process called the "proton-proton chain," a sequence of events that transforms four hydrogen atoms into one helium atom.

5 0
2 years ago
What is the heating curve on the horizontal line
nikklg [1K]

Answer:

The plateaus or horizontal lines on the graph represent the transition between states of the sample. The first plateau represents the melting (or transition from solid to liquid) and the second plateau represents boiling (or transition from liquid to gas).

Explanation:

7 0
3 years ago
Read 2 more answers
Phosphofructokinase is a four‑subunit protein with four active sites. Phosphofructokinase catalyzes step 3 of glycolysis, conver
svp [43]

Answer:

1. PEP is a feedback inhibitor of phosphofructokinase.

4. PEP inhibition of phosphofructokinase yields a sigmoidal velocity versus substrate curve.

6. The binding of PEP to one phosphofructokinase subunit causes a conformation change that affects the ability of the substrate to bind to the other subunits.

Explanation:

Phosphofructokinase-1, PFK-1, is an allosteric enzymes composed of four protein subunits.

Allosteric enzymes are enzymes that function through non-covalent binding of allosteric modulators which may be activators or inhibitors. They produce a characteristic velocity versus substrate sigmoidal curve. PFK-1 has a separate binding site for its substrate, fructose-6-phosphate and it's allosteric modulators: ATP, ADP or phosphoenolpyruvate, PEP.

The enzyme can exist in two conformations, the T-state (tense) or the R-state (resting). Binding of substrate causes a conformational change from T-state to R-state, whereas binding of allosteric inhibitors returns it to the T-state.

PEP, the product of step 9 in glycolysis, is an allosteric inhibitor of PFK-1. When it binds to the the allosteric site, it leads to conformational changes in PFK-1 from the R-state to the T-state which reduces the enzymes ability to bind the substrate. These changes are responsible for the sigmoidal velocity/substrate curve in allosteric enzymes.

Therefore, the true statements from the options above are 1, 4, 6.

Options 2,3 and 5 are wrong because PEP is a negative effector of PFK-1, thus its binding reduces the affinity of PFK-1 for its substrate. Also, PFK-1 being an allosteric enzyme has separate binding sites for its substrate and its modulators. Thus, there is no competition for active site binding by substrate and modulators.

5 0
3 years ago
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