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Alik [6]
3 years ago
9

A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What is the new v

olume? 0.0100 mL 0.325 mL 25.0 mL 100. mL
Chemistry
1 answer:
guapka [62]3 years ago
6 0

Ans: Final volume = 25.0 ml

<u>Given:</u>

Initial volume V1 = 50.0 ml

Initial pressure P1 = 20.0 atm

Final pressure P2 = 40.0 atm

<u>To determine:</u>

The final volume V2

<u>Explanation:</u>

Ideal gas equation: PV = nRT

under constant temperature, T and number of moles n we have:

PV = constant

or, P1V1 = P2V2

V2 = P1V1/P2 = 20*50/40 = 25 ml.

You might be interested in
How many moles are in 8.32 x 1024 molecules of CO2.
Andrews [41]

Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.32 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 13.820598...

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

6 0
3 years ago
state whether the following changes are physical or chemical for rancidipication fixation of water 2 tearing of paper 3 rusting
Artist 52 [7]
1. rancidification fixation of water is CHEMICAL CHANGE

2. Tearing of paper is PHYSICAL CHANGE

3. Rusting if iron is CHEMICAL CHANGE

4. Electrolysis of water is CHEMICAL CHANGE
5 0
3 years ago
Concert 15 cm3 to liters
musickatia [10]

The answer to your problem is 0.015 liters. I got the answer because to convert cubic centimeters into liters, you need to divide the cubic centimeters by 1000.

8 0
2 years ago
Need help !!!!! ASAP
Ksivusya [100]
<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of CO_{2}

n=0.120mol

<h2>Why?</h2>

We are asked to calculate the number of moles of the given gas, also, we  are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

R=62.363\frac{mmHg.L}{mol.K}

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°) + 273K

So, we are given the following information:

Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K

Now, isolating the number of moles, and substituting the given information, we have:

PV=nRT

n=\frac{PV}{RT}

n=\frac{PV}{RT}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole

Hence, we have that there were produced 0.120 moles of CO_{2}

n=0.120mol

Have a nice day!

7 0
3 years ago
Help will give brainliest!!
GarryVolchara [31]

Half reaction :

Oxidation

Cu ⇒ Cu²⁺ + 2e⁻

Reduction

2Ag⁺+ 2e⁻ ⇒2Ag  

<h3>Further explanation</h3>

Given

Reaction

Cu+2AgNO₃⇒Cu(NO₃)₂+2Ag

Required

Oxidation and reduction half-reactions

Solution

Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.

  • Oxidation

Cu ⇒ Cu²⁺ + 2e⁻

0 to +2

  • Reduction

2Ag⁺+ 2e⁻ ⇒2Ag  

+1 to 0

6 0
2 years ago
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