Chemical reaction: 4PBr₃(g) → P₄(g) + 6Br₂<span>(g).
</span>Pressure equilibrium constant (Kp) express the relationship between product pressures and reactant pressures. The partial pressures of gases are used to calculate pressure equilibrium constant.
Kp = (p(P₄) · p(Br₂)⁶) ÷ p(PBr₃)⁴.
p(P₄) - partial pressure of phosphorus.
p(Br₂) - partial pressure of bromine.
Ok so simple 1Ag2O ---> 1Ag+1O2 do u understand how I got that????
Answer:
0.0562
Explanation:
Ph=-log[H+]
to find the h+ is the antilogarithm of the Ph.
Which is 10 raised to the power - Ph.
Answer:
11.9 moles Cl₂
Explanation:
To find the number of moles, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = constant (0.0821 L*atm/mol*K)
-----> T = temperature (K)
Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.
P = 33.3 atm R = 0.0821 L*atm/mol*K
V = 11.5 L T = 120. °C + 273.15 = 393.15 K
n = ? moles
PV = nRT
(33.3 atm)(11.5 L) = n(0.0821 L*atm/mol*K)(393.15 K)
382.95 = n(0.0821 L*atm/mol*K)(393.15 K)
382.95 = (32.2776)n
11.9 = n
Answer:
Molarity of the packet is 0.5M
Explanation:
In the reaction of acetic acid with NaOH:
CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺
<em>1 mole of acetic acid reacts with 1 mole of NaOH.</em>
<em />
When you are titrating the acid with NaOH, you reach equivalence point when moles of acid = moles of NaOH.
Moles of NaOH are:
3.0mL = 3.0x10⁻³L ₓ (0.1 mol / L) =<em> 3.0x10⁻⁴ moles</em> of NaOH = moles of CH₃COOH.
Now, you find the moles of acetic acid in the hot sauce packet. But molarity is the ratio between moles of the acid and liters of solution.
As you don't know the volume of your packet, <em>you can assume its density as 1g/mL. </em>Thus, volume of 0.6g of hot sauce is 0.6mL = 6x10⁻⁴L.
And molarity of the packet is:
3.0x10⁻⁴ moles acetic acid / 6x10⁻⁴L =
<h3>0.5M</h3>
