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Temka [501]
2 years ago
7

Calculate the partial

Chemistry
1 answer:
Radda [10]2 years ago
6 0

The required partial pressure of argon gas present in the mixture is 1.02 atm.

<h3>What is Dalton law of gas?</h3>

Dalton's law of gas states that total pressure of any mixture of gas is sum of the partial pressure of all the gases present in that mixture.

Given that,

Total pressure of mixture = 2.4 atm

Partial pressure of argon = ?

Partial pressure of oxygen = 128 mmHg = 0.168 atm

Partial pressure of helium = 167.5 mmHg = 0.220 atm

Partial pressure of neon = 760 mmHg = 1 atm

On putting all these values according to the definition we get the partial pressure of argon gas as:
Partial pressure of argon = 2.4 - (0.168 + 0.22 + 1) = 1.02 atm

Hence required partial pressure of argon gas is 1.02 atm

To know more about Dalton's law, visit the below link:

brainly.com/question/8040766

#SPJ1

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When a 1.06 g sample of Compound Q, a nonelectrolyte, is dissolved in 11.6 g of water, the boiling point of the resulting soluti
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Answer:

The molar mass of compound Q is 100 g/mol

Explanation:

Step 1: Data given

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Mass of water = 11.6 grams

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Boiling point of water = 100.00 °C

Kb for water = 0.512 °C/m

Step 2: Calculate molality

ΔT = i*kb*m

⇒ with ΔT = the boiling point elevation = 0.47 °C

⇒ with i = the van't Hoff factor = 1

⇒ with kb = the boiling point elevation constant = 0.512 °C/m

⇒ with m = the molality = moles compound Q / mass water

m = ΔT / (i*Kb)

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m = 0.918 molal

Step 3: Calculate moles of Q

Molality = moles Q / mass H2O

moles Q = 0.918 molal * 0.0116 kg

moles Q = 0.0106 moles

Step 4: Calculate molar mass

Molar mass Q = mass Q / moles Q

Molar mass Q = 1.06 grams / 0.0106 moles

Molar mass Q = 100 g/mol

The molar mass of compound Q is 100 g/mol

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