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Stolb23 [73]
3 years ago
12

Which ion would represent the ion of an element from Group 2A?

Chemistry
1 answer:
ziro4ka [17]3 years ago
3 0

Answer:

E²⁺

Explanation:

The group two contain alkaline earth metals.

There are six elements in group 2A.

Beryllium, Magnesium, calcium, strontium, barium and radium.

All members have two valance electrons.

They lose two valance electrons to complete the octet.

When they lose the two valance electrons they form cation X²⁺.

They react with halogens and form salt such as

MgCl₂, CaCl₂ etc.

Mg²⁺  Cl²⁻₂

The oxidation state of halogens are -1, while the elements of group two A shows +2 that's why two atoms of halogen are combine with one atom of alkaline earth metals and make the compound overall neutral.

All the alkaline earth metals have similar properties.

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Explain why atoms would gain or lose electrons in order to resemble the elements in the particular group you named above. Consid
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Answer:

The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.

Explanation:

I hope that helps

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What are the benefits of hydro energy ?
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Its powered by water

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Students conduct an experiment:
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Answer:

The balloon becomes inflated

Explanation:

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You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions
artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

<em>You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.</em>

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

<em>1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.</em>

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

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<em>2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.</em>

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0
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forces along the vertical
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