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saw5 [17]
3 years ago
8

Why would it be better to be an r-selected species if the water resources in an area were to become more limited over a short pe

riod of time?
Also, sorry if this is the wrong subject, it was hard to find a fitting one for Environmental Science.
Chemistry
2 answers:
Ulleksa [173]3 years ago
7 0
Hello there!

It would be better to be an r-selected species if the water resources in an area were to become more limited because they tend to reproduce faster than other animals

Hope this helps! :)
Gnoma [55]3 years ago
6 0
An r-selected species reproduces much faster than K-selected species.

r-selected species focuses on maturing and reproducing quickly. r-selected species will probably reproduce when the water supply is there for the short period of time; thus, increasing the chance of the r-selected species of surviving.

K-selected species, on the other hand, focus on raising their young and reproduce later. Since the K-selected species take long to mature before reproducing, water supply may run out before they have a chance of fully maturing; thus, K-selected species have a lower chance of survival.

Hope this helps.
If you need anything more, feel free to comment! Have an awesome day! :)

~Collinjun0827, Junior Moderator
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2 years ago
The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e
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Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

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Let us assume that x concentration of N_{2}O_{4} is present at the initial stage. Therefore, according to the ICE table,

                    N_{2}O_{4} \rightarrow 2NO_{2}

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Change :       - 0.1        2 \times 0.1

Equilibrium : (x - 0.1)             0.2

Now, expression for K_{p} of this reaction is as follows.

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Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

                2 \times (x - 0.1) = (0.2)^{2}

                            x = 0.12

This means that P_{N_{2}O_{4}} = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

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Hey!!

here is your answer >>>

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