Explanation:
We are given: entropy of Fe2O3 = 90J/K.mol
: entropy of C = 5.7J/K.mol
: entropy of Fe = 27.2J/K.mol
: entropy of CO = 198J/K.mol

Answer:
The correct answer is C.
A i dolnt reaally know but yeh
Answer:
No, assuming that the salt/sugar is already dissolved
Explanation:
As long as the particle size is too big, it won't filter through. Therefore, if it is dissolved, it will pass through the filter.
If you were to throw rocks in there or something, and they are non-dissolvable, then yes.
Answer:
The answer to your question is 58.7 g of Ca(OH)₂
Explanation:
Data
mass of Ca(OH)₂ = ?
mass of HNO₃ = 100 g
Process
1.- Write the balanced chemical reaction
Ca(OH)₂ + 2HNO₃ ⇒ Ca(NO₃)₂ + 2H₂O
2.- Calculate the molar mass of the reactants
Ca(OH)₂ = 40 + 32 + 2 = 74 g
HNO₃ = 1 + 14 + 48 = 63 g
3.- Use proportions to calculate the mass of Ca(OH)₂
74 g of Ca(OH)₂ ----------------- 2(63) g of HNO₃
x ----------------- 100 g of HNO₃
x = (100 x 74) / 2(63)
x = 7400 / 126
x = 58.7 g