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3 years ago

If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater

Chemistry

2 answers:

agasfer [191]3 years ago

8 1

Answer:A. D. Y.

Explanation:

Disjsjjsdd

2 years ago

Ur dumb

Serggg [28]3 years ago

3 0

Answer: 1. ball A 2. their densities are equal 3. ball q 4. ball y

Explanation:

just took the test for them all right

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Need help ASAP please and thank you

Anna35 [415]

The answer is the second choice

5 0

3 years ago

fish tank initially contains 35 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 5 l

weeeeeb [17]

Answer:

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

Explanation:

Given:

Initial volume of water $V = 35$ lit

Flowing rate = 5 $\frac{Lit}{min}$

The rate of change in the amount of salt is given by,

$\frac{dx}{dt} =$ ( Rate of salt enters tank - rate of sat leaves tank )

Since tank is initially filled with water so we write that,

$x(0) = 0$

Let amount of salt in the solution is $c$ ,

$\frac{dx}{dt} = \frac{5c}{1 } - \frac{x(t) \times 5}{100}$

$\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$ $\frac{grams}{min}$

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

7 0

3 years ago

A certain substance X has a normal freezing point of −3.1°C and a molal freezing point depression constant =Kf·6.23°C·kgmol−1. C

muminat

Answer:

Freezing T° of solution = - 7.35 °C

Explanation:

This is about the freezing point depression, a colligative property which depends on solute.

The formula is: Freezing T° pure solvent - Freezing T° solution = m . Kf . i

Freezing T° of pure solvent is -3.1°C

At this case, i = 1. As an organic compound the urea does not ionize.

We determine the molality (mol/kg of solvent)

We convert mass to moles:

12.3 g . 1mol / 60.06 g = 0.205 moles

0.205 mol / 0.3 kg = 0.682 mol/kg

We replace data in the formula:

-3.1°C - Freezing T° of solution = 0.682 mol/kg . 6.23 kg°C/mol . 1

Freezing T° of solution = 0.682 mol/kg . 6.23 kg°C/mol . 1 + 3.1°C

Freezing T° of solution = - 7.35 °C

6 0

3 years ago

Water left in a a freezer is called

Masteriza [31]

Water left in a freezer is called ice

6 0

3 years ago

At present, cosmologists expect the universe to _____.

REY [17]

At present, cosmologists expect the universe to <span>continue expanding indefinitely and probably heating up.</span>

6 0

3 years ago

Read 2 more answers