Electrolyte is any species which when dissolved in solvent particularly water dissociates into cations and anions. Electrolytes are conductors of electricity. In given options;
CCl₄ (Tetrachloromethane) is a covalent compound. And it doesn't dissociate to any cation or anion. So it is not electrolyte.
SiO₂ (Silicon Dioxide) is also covalent in nature and exist in giant framework. It is not electrolyte.
Glucose (C₆H₁₂O₆) is also covalent compound. And doesn't produced any ion in water, hence it is not electrolyte.
H₂SO₄ (Sulfuric acid) is Electrolyte. When it is dissolved in water it produces H⁺ and SO₄²⁻ ions as follow,
H₂SO₄ → 2 H⁺ ₍aq₎ + SO₄²⁻ ₍aq₎
Result:
H₂SO₄ is electrolyte.
0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.
<h3>What is pressure?</h3>
Pressure is defined to be the amount of force exerted per area
80% of pressure is exerted by nitrogen gas.
So, 20% of pressure will be exerted by oxygen gas.
20% of 2.0 atm = 0.4 atm
Hence, 0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.
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Answer:
0.425 L
Explanation:
Given the information from the question. We know that the water heat evaporation is given by 2261 KJ/kg. Therefore, for each Kg of vapor, 2261 is required.
To calculate the amount of water evaporated by 960 KJ is as follows
= (1/2260)*960 =0.425 Kg
In other words, 0.425 of water is evaporated by 960 KJ.
To calculate the volume of water, we have mass and density. Therefore, Volume = Mass/Density = 425g/1g/ml = 0.425 L.
Therefore, water evaporated is 0.425 L
You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.
You can use a modified dilution formula to calculate the volume of 80 % alcohol
V1×C1 + V2×C2 = V3×C3
Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL
(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc
80x + 12 150 = 14 175 + 35 x
45x = 2025
x = 2025/45 = 45
Answer:
See below
Explanation:
PV = n RT R = .082057 L - Atm / (K-Mole)
.97 V = .118 (.082057)(305)
V = 3.04 liters
Will not change for argon.....will be the same for all ideal gases
