Answer:
The answer to your question is C₂H₆O
Explanation:
Data
Compound CxHyOz
mass of the sample = 0.9827
mass of CO₂ = 1.90 g
mass of H₂O = 1.070 g
Process
1.- Find the moles and grams of Carbon
44g of CO₂ ------------------ 12 g of C
1.9 g of CO₂ --------------- x
x = (1.9 x 12) / 44
x = 0.52 g
12 g of C --------------------- 1 mol
0.52 g -------------------- x
x = (0.52 x 1) / 12
x = 0.043 moles
2.- Find the moles and grams of Hydrogen
18 g of H₂O ----------------- 2 g of H
1.07 g of H₂O -------------- x
x = (1.07 x 2)/18
x = 0.12 g of H
1 g of H -------------------- 1 mol of H
0.12 g --------------------- x
x = (0.12 x 1)/1
x = 0.12 moles of H
3.- Calculate the moles and grams of Oxygen
Mass of Oxygen = 0.9827 - 0.12 - 0.52
= 0.3427 g
16 g of O ----------------- 1 mol
0.3427 g ---------------- x
x = (0.3427 x 1) / 16
x = 0.021 moles
4.- Divide by the lowest number of moles
Carbon 0.043 / 0.021 = 2
Hydrogen 0.12 / 0.021 = 5.7 ≈ 6
Oxygen 0.021 / 0.021 = 1
5.- Write the empirical formula
C₂H₆O
