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Artyom0805 [142]
3 years ago
6

Select the correct answer. An adult human lung has a volume of 2. 9 liters. If its volume decreases to 1. 2 liters and it contai

ns 0. 049 mole of air after it exhales, how many moles of air does it contain when full? A. 0. 025 mol B. 0. 041 mol C. 0. 083 mol D. 0. 12 mol E. 0. 14 mol.
Chemistry
1 answer:
maria [59]3 years ago
6 0

Moles are the ratio of the mass and the molar mass of the substance given and is estimated in mol. The moles that the lungs contain when it is full is 0.12 moles.

<h3>What is the relation of the volume and moles?</h3>

Moles of the substances are directly proportional to the volume of the substance and can be shown as,

\rm \dfrac{V_{1}}{V_{2}}= \dfrac{n_{1}}{n_{2}}

Here,

Initial volume \rm (V_{1}) = 2.9 L

Final volume \rm (V_{2}) = 1.2 L

Initial moles = \rm n_{1}

Final moles \rm (n_{2}) = 0.049 mol

Substituting values in the equation:

\begin{aligned} \dfrac{2.9}{1.2} &=\rm \dfrac{n_{1}}{0.049}\\\\&= \dfrac{2.9\times 0.049}{1.2}\\\\&= 0.12\;\rm mol\end{aligned}

Therefore, the number of moles in the lungs are 0.12 moles.

Learn more about moles and volumes here:

brainly.com/question/13909347

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Answer:

Explanation:

1) During the diagnosis of thyroid disease a 10 g sample of I-131 is used. After a period of 32 days, how much sample is still radio active.?

Answer:

0.625 g

Explanation:

HL = Elapsed time/half life

32 days/8 days = 4

At time zero = 10 g

At 1st half life = 10/2 = 5 g

At 2nd half life = 5/2 = 2.5 g

At 3rd half life = 2.5 /2 = 1.25 g

At 4th half life = 1.25 / 2 = 0.625 g

After 32 days still 0.625 g of I-131 remain radioactive.

2) what was the original mass of sample Tc-99 that was used to locate the brain tumor If 0.10 g of a sample remains after 30 days? (half life 6 days)

Answer:

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Half life = time elapsed / HL

Half life = 30 days / 6 days = 5

At 5th half life = 0.10 g

At 4th half life = 0.2 g

At 3rd half life =  0.4 g

At 2nd  half life = 0.8 g

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The original amount was 0.32 g.

3) write the beta decay equation of I-131?

Equation:

¹³¹I₅₃  →  ¹³¹Xe₅₄ + ⁰₋₁e

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

¹³¹I₅₃  →  ¹³¹Xe₅₄ + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

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Calcium carbonate is most likely to dissolve in water with:

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  • The reason behind the observation is the formation of Calcium bicarbonate which is soluble in water.
  • Higher concentration of Carbon dioxide in water turns it acidic. When this acidic water reacts with calcium carbonate it forms Calcium bicarbonate which is soluble in water.
  • So,Calcium carbonate is most likely to dissolve in water with lots of Carbon dioxide and colder temperature.
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