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Artyom0805 [142]
2 years ago
6

Select the correct answer. An adult human lung has a volume of 2. 9 liters. If its volume decreases to 1. 2 liters and it contai

ns 0. 049 mole of air after it exhales, how many moles of air does it contain when full? A. 0. 025 mol B. 0. 041 mol C. 0. 083 mol D. 0. 12 mol E. 0. 14 mol.
Chemistry
1 answer:
maria [59]2 years ago
6 0

Moles are the ratio of the mass and the molar mass of the substance given and is estimated in mol. The moles that the lungs contain when it is full is 0.12 moles.

<h3>What is the relation of the volume and moles?</h3>

Moles of the substances are directly proportional to the volume of the substance and can be shown as,

\rm \dfrac{V_{1}}{V_{2}}= \dfrac{n_{1}}{n_{2}}

Here,

Initial volume \rm (V_{1}) = 2.9 L

Final volume \rm (V_{2}) = 1.2 L

Initial moles = \rm n_{1}

Final moles \rm (n_{2}) = 0.049 mol

Substituting values in the equation:

\begin{aligned} \dfrac{2.9}{1.2} &=\rm \dfrac{n_{1}}{0.049}\\\\&= \dfrac{2.9\times 0.049}{1.2}\\\\&= 0.12\;\rm mol\end{aligned}

Therefore, the number of moles in the lungs are 0.12 moles.

Learn more about moles and volumes here:

brainly.com/question/13909347

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Gekata [30.6K]

Answer:

Be3As2

Explanation:

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2 years ago
A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

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3 years ago
Which of the following is an oxidation-reduction reaction? Fe2O3 3CO Right arrow. 2Fe 3CO2 CuSO4 2NaOH Right arrow. Cu(OH)2 Na2S
Damm [24]

The reaction, Fe2O3 + 3CO------> 2Fe + 3CO2 is an oxidation-reduction reaction.

An oxidation-reduction reaction is a reaction in which there is a change in oxidation number from left to right in the reaction. This is because, a specie is oxidized and another specie is reduced.

In the reaction;  Fe2O3 + 3CO------> 2Fe + 3CO2, we can see that the oxidation number of iron decreased from +3 on the left hand side to zero on the right hand side. The oxidation number of carbon was increased from + 2 to +4.

Learn more: brainly.com/question/10079361

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2 years ago
Radioactive isotopes of an atom are
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Less stable should be the answer.as I think
I hope this helps you
5 0
3 years ago
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How do you know if your hypothesis is supported by your results or not?
vivado [14]

Answer:

Your hypothesis is an educated guess of what the end results of an experiment will be, using what you already know about your experiment you are going to conduct. So when you receive your final results, if your hypothesis is correct, or even somewhat correct then you know that it is supported by your results. For example, if I were to conduct the Coca-Cola and Mentos experiment, I could make a hypothesis that the Coca-Cola will have a bigger eruption when I add more than one Mento to the bottle due to a higher amount of a chemical with the addition of each mento. When I receive my results that the eruption was bigger each time, I know that my results supported my hypothesis.

Explanation:

-Hope this helped

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