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Artyom0805 [142]
3 years ago
6

Select the correct answer. An adult human lung has a volume of 2. 9 liters. If its volume decreases to 1. 2 liters and it contai

ns 0. 049 mole of air after it exhales, how many moles of air does it contain when full? A. 0. 025 mol B. 0. 041 mol C. 0. 083 mol D. 0. 12 mol E. 0. 14 mol.
Chemistry
1 answer:
maria [59]3 years ago
6 0

Moles are the ratio of the mass and the molar mass of the substance given and is estimated in mol. The moles that the lungs contain when it is full is 0.12 moles.

<h3>What is the relation of the volume and moles?</h3>

Moles of the substances are directly proportional to the volume of the substance and can be shown as,

\rm \dfrac{V_{1}}{V_{2}}= \dfrac{n_{1}}{n_{2}}

Here,

Initial volume \rm (V_{1}) = 2.9 L

Final volume \rm (V_{2}) = 1.2 L

Initial moles = \rm n_{1}

Final moles \rm (n_{2}) = 0.049 mol

Substituting values in the equation:

\begin{aligned} \dfrac{2.9}{1.2} &=\rm \dfrac{n_{1}}{0.049}\\\\&= \dfrac{2.9\times 0.049}{1.2}\\\\&= 0.12\;\rm mol\end{aligned}

Therefore, the number of moles in the lungs are 0.12 moles.

Learn more about moles and volumes here:

brainly.com/question/13909347

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Answer : The molar mass of an acid is 266.985 g/mole

Explanation : Given,

Mass of an acid (HX) = 4.7 g

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First we have to calculate the moles of NaOH.

\text{Moles of }NaOH=\text{Molarity of }NaOH\times \text{Volume of solution}=0.54mole/L\times 0.0326L=0.017604mole

Now we have to calculate the moles of an acid.

In the titration, the moles of an acid will be equal to the moles of NaOH.

Moles of an acid = Moles of NaOH = 0.017604 mole

Now we have to calculate the molar mass of and acid.

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Now put all the given values in this formula, we get:

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