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meriva
3 years ago
6

Describe the path of a carbon atom through the process of cellular respiration? PLEASE HELP!!!!

Chemistry
1 answer:
balu736 [363]3 years ago
5 0
Chill man chilllllllllllllllllllllllllllllll
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\"Moving down group 2A (Alkaline Earth Metals), which element has the largest first ionization energy?\" Is the answer to this:
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Ionization energy is the energy required to remove the outermost electron from one mole of gaseous atom to produce 1 mole of gaseous in to produce a charge of 1. The greater the ionization energy, the greater is the chance f the electron to be removed from the nucleus. In this casse, Radium has the largest ionization energy.

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Which types of particles are charged and located within the nucleus of an atom?
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2 years ago
What does it mean when the electrons are excited??
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3 years ago
The equilibrium constant for the dissolution of silver chloride (AgCl(s) Ag+(aq) + Cl–(aq)) has a value of 1.79 × 10–10. Which s
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"Silver chloride is essentially insoluble in water" this statement is true for the equilibrium constant for the dissolution of silver chloride.

Option: b

<u>Explanation</u>:

As silver chloride is essentially insoluble in water but also show sparing solubility, its reason is explained through Fajan's rule. Therefore when AgCl added in water, equilibrium take place between undissolved and dissolved ions. While solubility product constant \left(\boldsymbol{K}_{s p}\right) for silver chloride is determined by equilibrium concentrations of dissolved ions. But solubility may vary also at different temperatures.  Complete solubility is possible in ammonia solution as it form stable complex as water is not good ligand for Ag+.  

To calculate \left(\boldsymbol{K}_{s p}\right) firstly molarity of ions are needed to be found with formula: \text { Molarity of ions }=\frac{\text { number of moles of solute }}{\text { Volume of solution in litres }}

Then at equilibrium cations and anions concentration is considered same hence:

\left[\mathbf{A} \mathbf{g}^{+}\right]=[\mathbf{C} \mathbf{I}]=\text { molarity of ions }

Hence from above data \left(\boldsymbol{K}_{s p}\right) can be calculated by: \left(\boldsymbol{K}_{s p}\right) = \left[\mathbf{A} \mathbf{g}^{+}\right] \cdot[\mathbf{C} \mathbf{I}]

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3 years ago
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