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ololo11 [35]
4 years ago
15

What is a caliper used for

Chemistry
1 answer:
photoshop1234 [79]4 years ago
8 0
To measure the distance between two opposite sides of an object
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Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol

x= 6.5mol of oxygen

6 0
2 years ago
Which one violates the octet rule?
Andrews [41]

Answer:

F1+ is the one that violates the octet rule

Explanation:

F1+  does not end up having 8 electrons in its valence shell, and there for violates the octet rule, for an atom to comply with the octet rule its charge must reflect the number of electrons it needs to gain or lose to make an octet, but F1+'s charge does not reflect the number of electrons it needs to be stable or have an electron configuration of a noble gas

5 0
3 years ago
The graph indicates the running route for Tobias.
Musya8 [376]

Answer: b

Explanation:

7 0
3 years ago
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Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
34kurt
To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol

C = 5.72 mol / 1.27 mol = 5
H = 10.79 mol / 1.27 mol = 8
O = 1.27 mol / 1.27 mol = 1

C5H8O
6 0
3 years ago
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An Alkali could have a pH of <br>A.1<br>B.5<br>C.7<br>D.9​
Free_Kalibri [48]

<em>7</em>

<em>Scientists use pH to describe how acidic a substance is on a scale of 0 to 14. By definition, a substance is alkaline if it has a pH of over 7.</em>

<em>mark </em><em>me</em><em> as</em><em> brilliant</em><em> pls</em><em> ❤️</em>

5 0
3 years ago
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