Answer:
2.18x10^-9 M
Explanation:
From the question given,
Hydrogen ion concentration, [H+] = 4.59x10^-6 M
Hydroxide ion, [OH-] =?
The hydroxide ion concentration, [OH-] in the solution can be obtained as follow:
[H+] x [OH-] = 1x10^-14
4.59x10^-6 x [OH-] = 1x10^-14
Divide both side by 4.59x10^-6
[OH-] = 1x10^-14 / 4.59x10^-6
[OH-] = 2.18x10^-9 M
Answer:
0.42 g
Explanation:
<u>We have: </u>
pH = 12.10 (25 °C)
V = 800.0 mL = 0.800 L
To find the mass of sodium hydroxide (NaOH) we can use the pH:


![pOH = -log ([OH^{-}])](https://tex.z-dn.net/?f=%20pOH%20%3D%20-log%20%28%5BOH%5E%7B-%7D%5D%29%20)
![[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-%7D%20%3D%2010%5E%7B-pOH%7D%20%3D%2010%5E%7B-1.90%7D%20%3D%200.013%20M)
Now, we can find the number of moles (η) of OH:
Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.
Finally, with the number of moles we can find the mass of NaOH:

<em>Where M is the molar mass of NaOH = 39.9 g/mol </em>

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.
I hope it helps you!
Carbohydrates are ring shaped.
Answer:
- <em>2.0 X 10²² molecules of AgNO₃</em>
Explanation:
Given 5.50 grams of AgNO₃, how many formula units of AgNO₃ are contained in the 5.50 grams of AgNO₃? (formula wt. of AgNO₃ = 169,87 g/mole).
Solution:
- 1st convert grams to moles => moles AgNO₃ = 5.50 g AgNO₃ / 169.841g AgNO₃ = 0.032377 mole AgNO₃
- 2nd calculate number of particles in 0.032377 mole AgNO₃
. Number AgNO₃ molecules in 0.032377 mole AgNO₃ = 0.032377 mole AgNO₃ X 6.023 x 10²³ molecules of AgNO₃ /1.0 mole AgNO₃ = 1.95007 X 10²² molecules of AgNO₃ in 5.50 grams of AgNO₃.
- The appropriate form of the answer should contain 2 Sig,Figs. based on the data point having the least number of sig.figs. in the given data. This then is 5.50 grams of AgNO₃ which has 2 sig.figs.
- <em>Therefore, the number of AgNO₃ molecules in 5.5 grams of AgNO₃ = 2.0 X 10²² molecules of AgNO₃.</em> (Note: 1.95 rounds to 2.0).
A.) Aluminum is the correct answer