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Scilla [17]
3 years ago
15

How do rivers affect watersheds?

Chemistry
2 answers:
sleet_krkn [62]3 years ago
6 0

Answer:

d

Explanation:

beks73 [17]3 years ago
5 0

Answer:

Explanation:

the last one I read it

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What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters
Gnom [1K]

Answer:

\boxed {\tt 1.0 \ g/mL}

Explanation:

Density can be found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

m= 50.0\ g \\v=50.0 \ mL

Substitute the values into the formula.

d=\frac{50.0 \ g}{50.0 \ mL}

Divide.

d= 1.0  \ g/mL

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

8 0
3 years ago
The ___________ energy in a mechanical system is determined by adding the potential and kinetic energy together
Anna35 [415]
I think its 

<span>The Mechanical energy in a mechanical system is determined by adding the potential and kinetic energy together. </span>

6 0
3 years ago
Read 2 more answers
What should go in the blank?
dem82 [27]

Answer:

³⁸₂₀Ca.

Explanation:

³⁸₁₉K –> __ + ⁰₋₁β

Let ʸₓA represent the unknown.

Thus the equation above can be written as:

³⁸₁₉K –> ʸₓA + ⁰₋₁β

Thus, we can obtain the value of y an x as follow:

38 = y + 0

y = 38

19 = x + (–1)

19 = x – 1

Collect like terms

19 + 1 = x

x = 20

Thus,

ʸₓA => ³⁸₂₀A => ³⁸₂₀Ca

Therefore, the equation is:

³⁸₁₉K –> ³⁸₂₀Ca + ⁰₋₁β

6 0
3 years ago
"To determine the amount of heroin in the mixture, you dissolve 1.00 g of the white powdery mixture in water in a 100.0-mL volum
UkoKoshka [18]

Explanation:

Formula to calculate osmotic pressure is as follows.

 Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = 25^{o} C

                      = (25 + 273) K

                      = 298.15 K  

Osmotic pressure = 531 mm Hg or 0.698 atm     (as 1 mm Hg = 0.00131)

Putting the given values into the above formula as follows.

       0.698 = C \times 0.082 \times 298.15 K&#10;

               C = 0.0285

This also means that,

  \frac{\text{moles}}{\text{volume (in L)}} = 0.0285

So,     moles = 0.0285 × volume (in L)

                      = 0.0285 × 0.100

                     = 2.85 \times 10^{-3&#10;}

Now, let us assume that mass of C_{12}H_{23}O_{5}N = x grams

And, mass of C_{12}H{22}O_{11} = (1.00 - x)

So, moles of C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}

                              = \frac{x}{369}

Now, moles of C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}

                   = \frac{x}{369} + \frac{(1.00 - x)}{342}

                  = 2.85 \times 10^{-3}

             = x = 0.346

Therefore, we can conclude that amount of C_{12}H_{23}O_{5}N present is 0.346 g  and amount of C_{12}H_{22}O_{11} present is (1 - 0.346) g = 0.654 g.

4 0
3 years ago
Fritz-Haber process
maks197457 [2]

Answer:

5×10⁵ L of ammonia (NH3)

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the balanced equation above, we can say that:

3 L of H2 reacted to produce 2 L of NH3.

Finally, we shall determine the volume of ammonia (NH3) produced by the reaction of 7.5×10⁵ L of H2. This can be obtained as illustrated below:

From the balanced equation above,

3 L of H2 reacted to produce 2 L of NH3.

Therefore, 7.5×10⁵ L of H2 will react to produce = (7.5×10⁵ × 2)/3 = 5×10⁵ L of NH3.

Thus, 5×10⁵ L of ammonia (NH3) is produced from the reaction.

6 0
3 years ago
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