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2 years ago

11

14 Orange-U-happy is an orange-scenteldeaning produthal is manu- factured in disposable doth pads. Each box of 100 pads sonts $5

to man. ufacture. The fixed costs for Orange-1-Hapoy a $30,000. The research development group of the company has determined the demand func- tion to her = 5000 - 20.060, where p is the price for each box a. Write the expense cuation in terms of the demand, b. Expres the expense function in terms of the price 9 c. Write the revenue function in terms of price. p.

1 answer:

kotykmax [81]2 years ago

4 0

Answer:

Consider the following statements, Each box of 100 pads of an orange-u happy costs$5 to manufacturer. The variable costs for manufacturing q boxes at 100 pads will be V=5.4

Step-by-step explanation:

You might be interested in

Function 1: y = 4x + 5

rosijanka [135]

Answer:

Option B is correct

Function 1, because the slope is 4 and the slope of function 2 is 2.

Step-by-step explanation:

Slope-intercept form:

The equation of line is given by:

$y=mx+b$

where, m is the slope and b is the y-intercept

As per the statement:

Function 1: y = 4x + 5

On comparing with [1] we have;

Slope of function 1 = 4

Function 2: The line passing through the points (1, 6) and (3, 10).

Using slope formula:

$\text{Slope}= \frac{y_2-y_1}{x_2-x_1}$

Substitute the given points we have;

$\text{Slope}= \frac{10-6}{3-1}$

⇒ $\text{Slope}= \frac{4}{2}$

Simplify:

⇒ $\text{Slope}=2$

⇒ $\text{Slope}= \frac{4}{2}$

⇒ Slope of the function 2 is, 2

Since, function 1 is greater rate of change.( i.e 4 > 2)

Therefore,

Function 1 has the greater rate of change, because the slope is 4 and the slope of function 2 is 2.

3 0

3 years ago

Read 2 more answers

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

a

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

b

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

So

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

So

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

3 years ago

Which value of HNK are used to write the function f(x) = x2 + 12x + 6 in vertex form?

anygoal [31]

Answer:

( − 6 , − 30 )

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex ( h , k ) .

6 0

3 years ago

A line's y-intercept is -3.7 and it's slope is

liberstina [14]

Y= 8.4x-3.7 i think

8 0

2 years ago

10. On one night, a group of 9 rats carried away 45 kg of food. What is the reduced ratio of rats to food weight

GenaCL600 [577]

Answer:

Number of rats : Food weight = 1 : 5

Step-by-step explanation:

Number of rats in the group = 9

Weight of food carried away by them = 45 kg

Ratio of the number of rats and food weight = $\frac{\text{Number of rats}}{\text{Weight of food carried by the rats}}$

= $\frac{9}{45}$

= $\frac{1\times 9}{5\times 9}$

= $\frac{1}{5}$

Therefore, Number of rats : Food weight = 1 : 5

4 0

3 years ago