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2 years ago

how many 3 digit positive numbers have their hundreds, tens, and units digits in strictly ascending order

1 answer:

6 0

There are seven 3 digit positive numbers that have their hundreds, tens, and units digits in strictly ascending order

Since the hundreds, tens, and units digits are in strictly ascending order.

Let the digit in hundreds place be n, since its is strictly ascending order, the digit in the tens place is n + 1 and the digit in the units place is n + 2.

So, the digits are n, n + 1, n + 2.

<h3>The positive 3 digit numbers</h3>

So, starting with n = 1, we find the number of 3 digit positive integers in ascending order.

n, n + 1, n + 2.

1, 1 + 1, 1 + 2.

1, 2, 3

So, the first number is 123

n, n + 1, n + 2.

2, 2 + 1, 2 + 2.

2, 3, 4

So, the second number is 234

n, n + 1, n + 2.

3, 3 + 1, 3 + 2.

3, 4, 5

So, the third number is 345

n, n + 1, n + 2.

4, 4 + 1, 4 + 2.

4, 5, 6

So, the fourth number is 456

n, n + 1, n + 2.

5, 5 + 1, 5 + 2.

5, 6, 7

So, the fifth number is 567

n, n + 1, n + 2.

6, 6 + 1, 6 + 2.

6, 7, 8

So, the sixth number is 678

n, n + 1, n + 2.

7, 7 + 1, 7 + 2.

7, 8, 9

So, the seventh number is 789

n, n + 1, n + 2.

8, 8 + 1, 8 + 2.

8, 9, 10

Since we cannot have 10 in the last digit, we ignore this number.

<h3>The 3 digit positive numbers</h3>

So, the numbers are 123, 234, 345, 456, 567, 678, and 789

So, there are seven 3 digit positive numbers that have their hundreds, tens, and units digits in strictly ascending order

Learn more about positive numbers here:

brainly.com/question/23270521

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Evaluate tan 11 pi/6

Nadusha1986 [10]

Answer:

tan 11 pi dived by 6 is equal to -118.307586549

4 0

3 years ago

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

tatiyna

F(x) = 4 - x² g(x) = 6x

(g - f)(x) = g(x) - f(x)

(g - f)(3) = g(3) - f(3)

g(x) = 6x

g(3) = 6*3 = 18

f(x) = 4 - x²

f(3) = 4 - 3² = 4 - 9 = -5

(g - f)(3) = g(3) - f(3) = 18 - (-5) = 18 + 5 = 23

(g - f)(3) = 23

7 0

3 years ago

We know that a triangle with side lengths , , and is a right triangle. Using those side lengths, find the missing triples and x-

Anit [1.1K]

The completed table for the Pythagorean triples are:

$x \text{ value } \text{ Pythagorean triple}\\\text{ } \text{ } \text{ } 3 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (6,8,10)\\\text{ } \text{ } \text{ } 4 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (8,15,17)$

$\text{ } \text{ } \text{ } 5 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (10,24,26)\\\text{ } \text{ } \text{ } 6 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (12,35,37)$ .

A trio of positive numbers known as a Pythagorean triple fits into the Pythagoras theorem's formula, which is written as a² + b² = c², where a, b, and c are all positive integers. Here, "a" and "b" make up the other two legs of the right-angled triangle, and "c" serves as the triangle's "hypotenuse," or longest side. In terms of the Pythagorean triples (a, b, c).

In the question, we are given that a triangle with side lengths x² - 1, 2x, x² + 1 is a right triangle, and are asked to fill in the missing table:

$x \text{ value } \text{ Pythagorean triple}\\\text{ } \text{ } \text{ } 3 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \underline{\text{ }}\\\text{ } \text{ } \text{ } \underline{\text{ }} \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (8,15,17)\\$

$\text{ } \text{ } \text{ } 5 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \underline{\text{ }}\\\text{ } \text{ } \text{ } \underline{\text{ }} \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (12,35,37)$ .

Taking x as 3, and putting in the sides, we get:

x² + 1 = 3² + 1 = 10.

2x = 2*3 = 6.

x² - 1 = 3² - 1 = 8.

Thus, the triplet is 6,8,10.

For the triplet 8,15,17, we get the x value as:

2x = 8,

or, x = 8/2 = 4.

Thus, the x-value for the triplet (8,15,17) is 4.

Taking x as 5, and putting in the sides, we get:

x² + 1 = 5² + 1 = 26.

2x = 2*5 = 10.

x² - 1 = 5² - 1 = 24.

Thus, the triplet is 10,24,26.

For the triplet 12,35,37, we get the x value as:

2x = 12,

or, x = 12/2 = 6.

Thus, the x-value for the triplet (12,35,37) is 6.

Thus, the completed table for the Pythagorean triples are:

Learn more about the Pythagorean triplets at

brainly.com/question/24211694

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The provided question is incomplete. The complete question is:

"We know that a triangle with side lengths x² - 1,2x and x² + 1 is a right triangle. Using those side lengths, find the missing triples and x-values.

Write the triples in parentheses, without spaces between the numbers, and with a comma between numbers. Write the triples in order from least to greatest.

Type the correct answer in each box.

$x \text{ value } \text{ Pythagorean triple}\\\text{ } \text{ } \text{ } 3 \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \underline{\text{ }}\\\text{ } \text{ } \text{ } \underline{\text{ }} \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } \text{ } (8,15,17)\\$

6 0

2 years ago

PLS ANSWER QUICK THANK YOU

insens350 [35]

B!!!!!!

Step-by-step explanation:

$5 \times {10}^{4} \times 9.46\times {10}^{12} = {4.73} \times {10}^{17}$