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Sonja [21]
2 years ago
15

If the resistance in a series circuit is 12 K Ohms, and the amperage is 0. 0063 amps, what is the voltage?

Engineering
1 answer:
kkurt [141]2 years ago
3 0

Answer:

The resistance “seen” by the 12-Volt battery is 500 ohms . The total resistance is the sum of the resistors R1 and R2. Each resistor will drop a calculable amount of voltage. This voltage is given by Ohm's Law.

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A 4-lb ball B is traveling around in a circle of radius r1 = 3 ft with a speed (vB)1 = 6 ft>s. If the attached cord is pulled
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Answer:

r₂ = 1.5 ft

t = 0.75 s

Explanation:

W = 4 lb    ⇒  m = W/g = 4 lb / 32.2 ft/s² = 0.12 slug

v₁ = 6 ft/s

r₁ = 3 ft

v₂ = 12 ft/s

r₂ = ?

t = ?

vr = 2 ft/s

Conserving angular momentum we have:

m*v₁*r₁ = m*v₂*r₂    ⇒     r₂ = v₁*r₁ / v₂

⇒     r₂ = (6 ft/s*3 ft) / (12 ft/s) = 1.5 ft

Now, we get the time as follows:

vr = <em>d</em> / t    ⇒   t = <em>d</em> / vr

where <em>d</em> is

<em>d</em> = Δr = r₁ - r₂ = 3 ft - 1.5 ft = 1.5 ft

finally

t = 1.5 ft / 2 ft/s

⇒ t = 0.75 s

5 0
3 years ago
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Answer:

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