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Fynjy0 [20]
4 years ago
10

A Pitot-static probe is used to measure the speed of an aircraft flying at4000 m. Assume that the density of the atmosphere at t

hat height is 0.82 kg/m3. Ifthe differential pressure reading is 3.5 kPa, determine the speed of the aircraft.
Engineering
1 answer:
Ray Of Light [21]4 years ago
4 0

Answer:

The speed of the aircraft is  V_1 = 92.0 \ \frac{m}{s}

Explanation:

Assumptions.

1. flow of air is steady & incompressible.

2. Frictional effects are neglected.

From the Bernoulli's equation

The velocity of the jet is given by  

V_{1} = \sqrt{2(\frac{P_2 - P_1}{\rho}) }

Here P_2 -P_1 = 3500 \ Pa

\rho = 0.82 \frac{kg}{m^{3} }

Thus velocity

V_{1} = \sqrt{2(\frac{3500}{\ 0.82}) }

V_1 = 92.0 \ \frac{m}{s}

Therefore the speed of the aircraft is  V_1 = 92.0 \ \frac{m}{s}

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A copper block receives heat from two different sources: 5 kW from a source at 1500 K and 3 kW from a source at 1000 K. It loses
LUCKY_DIMON [66]

Answer:

a) Zero

b) the rate of entropy generation in the system's universe = ds/dt = 0.2603 KW/K

Explanation:

a) In steady state  

Net rate of Heat transfer = net rate of heat gain -  net rate of heat lost  

Hence, the rate of heat transfer = 0

b) In steady state, entropy generated  

ds/dt = - [ Qgain/Th1 + Qgain/Th2 - Qlost/300 K]

Substituting the given values, we get –  

ds/dt = -[5/1500 + 3/1000 – (5+3)/300]

ds/dt = - [0.0033 + 0.003 -0.2666]

ds/dt = 0.2603 KW/K

 

6 0
3 years ago
The Environmental Protection Agency (EPA) has standards and regulations that says that the lead level in soil cannot exceed the
DENIUS [597]

Answer:

See below

Explanation:

<u>Check One-Sample T-Interval Conditions</u>

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

<u>One-Sample T-Interval Information</u>

  • Formula --> CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})
  • Sample Mean --> \bar{x}=390.25
  • Critical Value --> t^*=2.0096 (given df=n-1=50-1=49 degrees of freedom at a 95% confidence level)
  • Sample Size --> n=50
  • Sample Standard Deviation --> S_x=30.5

<u>Problem 1</u>

The critical t-value, as mentioned previously, would be t^*=2.0096, making the 95% confidence interval equal to CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

3 0
2 years ago
The Double.parseDouble() method requires a String argument, but it fails if the String cannot be converted to a floating-point n
LuckyWell [14K]

Answer:

  1. import java.util.Scanner;
  2. public class TryToParseDouble {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        double num;
  6.        try{
  7.            System.out.print("Input a number: ");
  8.            num = Double.parseDouble(input.nextLine());
  9.        }catch(NumberFormatException e){
  10.            num = 0;
  11.            System.out.println("Invalid input! It should be a number in double type");
  12.        }
  13.        System.out.println(num);
  14.    }
  15. }

Explanation:

Firstly, create a Scanner object to get user input (Line 5).

Next, create a try block and prompt user to input a number and use Double.parseDouble() method to convert the input to double type in the block (Line 8-10).

Next, create a catch block to catch a NumberFormatException. In the Catch block, set the num to zero and then print out a message to inform user about the invalid input (Line 12-14).

Lastly, display the number (Line 16).

5 0
3 years ago
Acoke can with inner diameter(di) of 75 mm, and wall thickness (t) of 0.1 mm, has internal pressure (pi) of 150 KPa and is suffe
NemiM [27]

Answer:

All 3 principal stress

1. 56.301mpa

2. 28.07mpa

3. 0mpa

Maximum shear stress = 14.116mpa

Explanation:

di = 75 = 0.075

wall thickness = 0.1 = 0.0001

internal pressure pi = 150 kpa = 150 x 10³

torque t = 100 Nm

finding all values

∂1 = 150x10³x0.075/2x0,0001

= 0.5625 = 56.25mpa

∂2 = 150x10³x75/4x0.1

= 28.12mpa

T = 16x100/(πx75x10³)²

∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]

= 1/2[84.37±√791.2969+5.827396]

= 1/2[84.37±28.33]

∂1 = 1/2[84.37+28.33]

= 56.301mpa

∂2 = 1/2[84.37-28.33]

= 28.07mpa

This is a 2 d diagram donut is analyzed in 2 direction.

So ∂3 = 0mpa

∂max = 56.301-28.07/2

= 14.116mpa

6 0
3 years ago
2. It is a measuring instrument used to record the amount of
lyudmila [28]

Answer:

The correct option is;

D. Electric meter

Explanation:

An electric meter is a metering device that is used for the measurement of the electric power consumption of an electrical powered tools, a living space or a building

Electric meter readings are used by electric utility company to sell electric power to consumers at a given rate such that it allows the electric utility company to receive payment for the total power supplied, and for the consumer to regulate the amount of power consumed

The electric meters are usually calibrated in kilowatt hour (kWh) and prepaid meter displays the amount of units of power bought, while post paid meters are usually read once each billing period which is usually one month.

3 0
3 years ago
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