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Serga [27]
3 years ago
5

Which of the following are tips to help a speaker use their own voice?

Engineering
2 answers:
Sergeu [11.5K]3 years ago
7 0

Answer: D

Explanation:

djverab [1.8K]3 years ago
4 0
D) All of the above.
You might be interested in
3.8. Describe the two alternatives for specifying structural constraints on relationship types. What are the advantages and disa
forsale [732]

Answer: CARDINALITY RATIO AND PARTICIPATION

ADVANTAGE

CARDINALITY RATIO

(THEY ARE USED TO SIMPLIFY DESIGNS)

DISADVANTAGE OF CARDINALITY RATIO IS THAT

(YOU CAN NOT SPECIFY A GIVEN NUMBER TO BE MAXIMUM)

ADVANTAGE OF PARTICIPATION CONSTRAINT IS THAT

(IT SHOWS WETHER THE EXISTENCE OF AN ENTITY IS DEPENDENT ON ITS RELATIONSHIPS WITH ANOTHER ENTITY)

DISADVANTAGE OF PARTICIPATION CONSTRAINT

(IT IS A COSTLY AFFAIR USING BOTH MODELS TO EXPRESEE RELATIONSHIPS).

Explanation:CARDINALITY RATIO specifies that maximum number of relationships an entity can engage itself in.

Participation constraint is a constraint that

Specifies whether the existence of an entity depends on its Relationships to another entity, it specifies the the minimum number of relationship instances that an entity can participate in

It is also minimum cardinality constraint,it has two types named as Total participation and partial participation.

7 0
4 years ago
Entrence is one of the animation category​
krek1111 [17]

Answer:Videos

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Explanation:

3 0
3 years ago
Consider a Pitot static tube mounted on the nose of an experimental airplane. A Pitot tube measures the total pressure at the ti
kotykmax [81]

Answer:

M∞ = 0.53

M∞ = 1.5

M∞ = 3.1

Explanation:

Find: For each case the free stream Mach number.

-Pitot pressure=1.22×10^5N/m2 , static pressure=1.01 × 10^5N/m2 .

Solution:

- The free stream Mach number is a function of static to hydrodynamic pressures. So for this case we have:

            P = 1.01 × 10^5 .. static pressure

            Po = 1.22×10^5   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            P / Po = (1.01 × 10^5) / (1.22×10^5) = 0.8264.

- Use Table A.13 and look up the ratio P/Po = 0.8264 for Mach number M∞.

            M∞ = 0.53

Find:

-Pitot pressure=7222 lb/ft^2 , static pressure=2116 lb/ft^2

Solution:

- The free stream Mach number is a function of static to hydrodynamic pressures. So for this case we have:

            P = 2116 .. static pressure

            Po = 7222   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            P / Po = (2116) / (7222) = 0.2930.

- However, since this is supersonic, a normal shock sits in front of the Pitot tube.  Hence, Po is now the total pressure behind a normal shock wave. Thus, we have  to use Table A.14.

            P1 = 2116 .. static pressure

            Po2 = 7222   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            Po2 / P1 = (7222) / (2116) = 3.412.

- Use Table A.14 and look up the ratio Po2/P1 = 3.412 for Mach number M∞.

            M∞ = 1.5

Find:

-Pitot pressure=13197 lb/f^t2 , static pressure=1020 lb/ft^2

Solution:

- The free stream Mach number is a function of static to hydrodynamic pressures. So for this case we have:

            P = 1020 .. static pressure

            Po = 13197   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            P / Po = (1020) / (13197) = 0.0772.

- Again, since this is supersonic, a normal shock sits in front of the Pitot tube.  Hence, Po is now the total pressure behind a normal shock wave. Thus, we have  to use Table A.14.

            P1 = 1020 .. static pressure

            Po2 = 13197   ... pitot pressure ( hydrodynamic )

- Take the ratio:

            Po2 / P1 = (13197) / (1020) = 12.85.

- Use Table A.14 and look up the ratio Po2/P1 = 12.85 for Mach number M∞.

            M∞ = 3.1

3 0
3 years ago
Given the following phasors and the information related to the frequency of that phasor, provide the corresponding time-domain r
Evgesh-ka [11]

Answer:

Explanation:

In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.

For the step by step solution to the question you asked, go through the attached documents.

4 0
3 years ago
In this homework problem we’ll begin completing an implementation of SimpleList that uses a linked list of Item objects internal
balu736 [363]

The solution contains multiple java files. The initial linked list is 10 20 30 40 . The modified list is 20 30 40

<u>Explanation</u>

//Define the interface SimpleList;

public interface SimpleList

{

   public Object get (int index);

   public void set (int index, Object element);

   public void add (int index, Object element);

   public Object remove(int index);

   public int size();

}

SimpleLinkedList.java:

//Define the class SimpleLinkedList that implements the SimpleList.

public class SimpleLinkedList implements SimpleList

{

   //Define the Item class.

   class Item

   {

       Object value;

       Item next;          

       Item (Object setValue, Item setNext)

       {

           value = setValue;

           next = setNext;

       }

   }      

   protected Item start;

   protected int currentSize;      

   //Define the default constructor.

   public SimpleLinkedList()

   {

       currentSize = 0;

       start = null;

   }      

   //Define the parameterized constructor.

   SimpleLinkedList(Object[] values)

   {

       currentSize = 0;          

       //Start the loop and call the add method.

       for(int i = 0; i<values.length;i++)

       {

           add(i, values[i]);

       }

   }      

   //Define the method to return the object

   // at the given index.

   atOverride

   public Object get (int index)

   {

       //Call the getItem() method and return it's value.

       return getItem(index).value;

   }      

   //Define the set() method.

   atOverride

   public void set (int index, Object element)

   {

       if (index < 0 || index >= currentSize)

       {

           return;

       }

       int currentIndex = 0;          

       for (Item current = start; current != null; current = current.next)

       {

           if (currentIndex == index)

           {

               current.value = element;

               break;

           }

           currentIndex++;

       }

   }    

   //Define the getItem() method.

   protected Item getItem(int index)

   {

       if (index < 0 || index >= currentSize)

       {

           return null;

       }      

       int currentIndex = 0;        

       for (Item current = start; current != null; current = current.next)

       {

           if (currentIndex == index)

           {

               return current;

           }

           currentIndex++;

       }

       return null;

   }      

   //Define the add() method.

   atOverride

   public void add (int index, Object toAdd)

   {

       if (index == 0)

       {

           start = new Item (toAdd, start);

           currentSize++;

           return;

       }        

       Item previousItem = getItem(index - 1);        

       if(previousItem == null)

       {

           return;

       }          

       Item newItem = new Item(toAdd, previousItem.next);

       previousItem.next = newItem;

       currentSize++;

   }      

   //Define the method to return the size of the linked list.

   atOverride

   public int size ()

   {

       return currentSize;

   }      

   //Define the method to remove an index from the linked list.

   atOverride

   public Object remove (int index) {

       // TODO Auto-generated method stub

       return null;

   }      

}

YourSimpleLinkedList.java:

//Define the YourSimpleLinkedList class.

public class YourSimpleLinkedList extends SimpleLinkedList

{

   //Define the default constructor.s

   public YourSimpleLinkedList()

   {

       super();

   }      

   //Define the parameterized constructor.

   YourSimpleLinkedList(Object[] values)

   {

       super(values);

   }

   //Define the method to remove an index.

   at Override

   public Object remove(int index)

   {

       //Return null if the index is out of range.

       if (index < 0 || index >= currentSize)

       {

           return null;

       }        

       //Set the start Item if the first value

       // is to be removed.

       if (index == 0)

       {

           //Store the value of the node to be removed.

           Object temp = start.value;

           

           //Set the start Item.

           start = start.next;

           

           //Update the size of the linked list and return

           // the deleted value.

           currentSize--;

           return temp;

       }        

       //Initialize the required variables.

       int currentIndex = 0;

       Item current = start;

       Item prev = start;        

       //Start the loop to traverse the list.

       while (current != null)

       {

           //Check the index value.

           if (currentIndex == index)

           {

               //Store the value to be deleted.

               Object temp = current.value;                

               //Set the next pointer.

               prev.next = current.next;                  

               //Update the size of the linked list and return

               // the deleted value.

               currentSize--;

               return temp;

           }            

           //Update the values.

           currentIndex++;

           prev = current;

           current = current.next;

       }

       return null;

   }

}

Main.java:

public class Main

{

   public static void main(String[] args)

   {

       //Create a list of objects.

       Object [] values = {10, 20, 30, 40};          

       //Create an object of the YourSimpleLinkedList class.

       YourSimpleLinkedList myList = new YourSimpleLinkedList(values);        

       //Display the initial list.

       System.out.print("The initial linked list is ");

       for (int i=0;i<myList.size();i++)

       {

           System.out.print(myList.get(i) + " ");

       }        

       //Remove an index from the list.

       myList.remove(0);        

       //Display the modified list.

       System.out.println();

       System.out.print("The modified list is ");

       for (int i=0;i<myList.size();i++)

       {

           System.out.print(myList.get(i) + " ");

       }

   }  

}

5 0
4 years ago
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