Write the closed-loop transfer function for the system and determine the closed-loop pole locations. Is the closed-loop system s
table? (4 pts) b) Determine the damping ratio ζζ and the natural frequency ????????nn of the closed loop system. (2 pts) c) Use inverse Laplace and partial fraction expansion to find the solution yy(tt) to a unit step input in RR? (5 pts) d) Sketch as accurately as possible the time response of the above system to a unit step input in R. Show all relevant time-domain specification calculations used in sketching your response. (
1 answer:
Answer:
Check the explanation
Explanation:
To write the closed-loop transfer function for the system and determine the closed-loop pole locations as well as to determine the damping ratio and the natural frequency, we will be be doing a step by step calculation and explanation including the graphical presentation as seen in the attached images below.
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Answer:
Power output,
Given:
Pressure of steam, P = 1400 kPa
Temperature of steam,
Diameter of pipe, d = 8 cm = 0.08 m
Mass flow rate,
Diameter of exhaust pipe,
Pressure at exhaust, P' = 50 kPa
temperature, T' =
Solution:
Now, calculation of the velocity of fluid at state 1 inlet:
Now, eqn for compressible fluid:
Now,
Now, the power output can be calculated from the energy balance eqn:
Answer:
44.59°c
Explanation:
Given data :
Total pressure = 105 kpa
complete combustion
A) Determine air-fuel ratio
A-F =
N = number of mole
m = molar mass
A-F = = 22.2 kg air/fuel
hence the ratio of Fuel-air = 1 : 22.2
B) Determine the temperature at which water vapor in the products start condensing
First we determine the partial pressure of water vapor before using the steam table to determine the corresponding saturation temp
partial pressure of water vapor
Pv =
N watervapor ( number of mole of water vapor ) = 3
N pro ( total number of mole of product = 3 + 3 + 2.25 + 25.28 = 33.53 kmol
Pro = 105
hence Pv = ( 3/33.53 ) * 105 = 9.39kPa
from the steam pressure table the corresponding saturation temperature to 9.39kPa = 44.59° c
Temperature at which condensing will start = 44.59°c
An equation showing the products of propylene with their mole numbers is attached below
