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julia-pushkina [17]
2 years ago
14

A soccer player kicks a ball at rest on the

Physics
1 answer:
scoundrel [369]2 years ago
5 0

The kinetic energy and gravitational potential energy changes during its movement from ground to the top height.

<h3>What happens to kinetic and potential energy while motion?</h3>

When the ball moves upward, its gravitational potential energy is increases and kinetic energy begins to decrease but when the ball falls towards the earth, its gravitational potential energy is transformed into kinetic energy. When the ball collides with the ground, the kinetic energy is transformed into other forms of energy.

Learn more about kinetic energy here: brainly.com/question/20658056

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A ball rolls 50 meters in
-Dominant- [34]

The speed of the ball is B. 5 meters per second

Explanation:

For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation

v=\frac{d}{t}

where

v is the speed

d is the distance covered

t is the time taken

For the ball in this problem:

d = 50 m is the distance covered

t = 10 s is the time taken

Substituting, we find the speed:

v=\frac{50}{10}=5 m/s

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

3 0
3 years ago
You observe a distant galaxy. you find that a spectral line normally found in the visible part of the spectrum is shifted toward
MrRissso [65]
The galaxy is moving away from you.

6 0
3 years ago
A long, thin rod parallel to the y-axis is located at x = -1.0 cm and carries a uniform linear charge density of +1.0 nC/m. A se
Bad White [126]

Answer:

Hhere is the other part of the question ; What is the net electric field due to these rods at the origin? (epsilon not = 8.85*10^-12)

net electric field = 3600N/C

Explanation:

The detailed calculation is as shwon below

8 0
3 years ago
Consider horizontal parallel plates with a fixed potential difference. The upper plate has a voltage difference of 30 V with the
BlackZzzverrR [31]

relation between potential difference and electric field is given as

E . d = \Delta V

so here we know that

d = 3 cm

\Delta V = 30 V

E \times 0.03 = 30

E = 1000 N/C

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

5 0
3 years ago
Find the instantaneous acceleration at t=ls for an object moving along a straight axis with velocity function:
Maru [420]
The answer is A.
Explanation:
We know that the average acceleration a for an interval of time Δt is expressed as:

a = Δv
Δt
where Δv is the change in velocity that occurs during Δt.
e formula for the instantaneous acceleration a is almost the same, except that we need to indicate that we're interested in knowing what the ratio of Δv to Δt approaches as Δt approaches zero.

We can indicate that by using the limit notation.

So, the formula for the instantaneous acceleration is:

a = lim Δv
Δt→0 Δt
8 0
3 years ago
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