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choli [55]
3 years ago
11

Which phrases describe all the outer planets motion? Select two options

Physics
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

slow revolution and  fast rotation

Explanation:

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The tools to distinguish the thickness of two objects of thickness of 1.92mm and the other with thickness of 1.93mm is ?
melomori [17]

Answer:

the instrument that gives this precision is the micrometer screw

Explanation:

The high precision measurements of small parts are the general vernier and the micrometer screw.

In these two instruments the same principle is used: there is a fixed rule and a mobile one that increases precision.

Let's analyze the absolute error or precision of each instrument

* For the vernier, the precision of the fixed rule is 1 mm and there are 20 divisions (the most common); therefore the precision of the instrument is

            Δx = 1 mm / 20

            Δx = 0.05 mm

* For the micrometer screw, the precision of the fida rule is 0.5 mm and the number of divisions is 50, therefore the precision of the screw is

            Δx = 0.5mm / 50

            Δx = 0.01 mm

consequently the instrument that gives this precision is the micrometer screw

8 0
3 years ago
A ray diagram is shown.
Svetlanka [38]

Answer:

It is virtual and behind the mirror

Explanation:

When an image is produced by a mirror, we have the following situations:

- The image is said to be in front of the mirror if it is on the same side of the object, with respect to the mirror

- The image is said to be behind of the mirror if it is on the opposite side of the object, with respect to the mirror

Moreover:

- The image is said to be real if it is in front of the mirror

- The image is said to be virtual if it is behind the mirror

In this case, the image (located at point I) is on the opposite side of the object (located at point O), so it is virtual and behind the mirror.

6 0
4 years ago
Read 2 more answers
Need help with this question. Thirty points.
Anon25 [30]

1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v  = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\

4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J

5 0
2 years ago
Reacting with water in an acidic solution at a particular​ temperature, compound A decomposes into compounds B and C according t
Diano4ka-milaya [45]

Answer:

after  t = 3 hours compound A remain 0.396 M

t = 12.98 hours

Explanation:

P = P_0*e^(-kt)  

t = 30 minutes = 30/60 hours = 0.5 hours

and P_0 = 0.60M

and P after t = 0.5 hours is 0.56 M

(0.56/0.6) = e^(-kt)

0.933 =e^(-kt)

k = 0.138

P = P_0*e^(-0.138t)

Now after  t = 3 hours,

P = 0.6* e^((-0.138)*3) = 0.396 M

time  when P = 0.1 M

0.1 = 0.6*e^(-0.138t)

t = 12.98 hours

8 0
3 years ago
A Carnot engine operates with an efficiency of 26.0% when the temperature of its cold reservoir is 281 K. Assuming that the temp
VLD [36.1K]

Answer:

The temperature of cold reservoir should be 246.818 K for efficiency of 35%

Explanation:

In first case we have given efficiency of Carnot engine = 26 % = 0.26

Temperature of cold reservoir T_L=281K

We know that efficiency of Carnot engine is given by

\eta =1-\frac{T_L}{T_H}

0.26 =1-\frac{281}{T_H}

T_H=379.72K

For second Carnot engine efficiency is given as 35% = 0.35

And temperature of hot reservoir is same so T_H=379.72K

So 0.35=1-\frac{T_L}{379.72}

T_L=246.818K

So the temperature of cold reservoir should be 246.818 K for efficiency of 35%

4 0
4 years ago
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