Air resistance, also called drag, acts upon a falling body by slowing the body down to thr point where it stops accelerating, and it falls at a constant speed, known as the terminal volocity of a falling object. Air resistance depends on the cross sectional area of the object, which is why the effect of air resistance on a large flat surfaced object is much greater than on a small, streamlined object.
Answer:
Explanation:
initial angular velocity, ωo = 0 rad/s
angular acceleration, α = 30.5 rad/s²
time, t = 9 s
radius, r = 0.120 m
let the velocity is v after time 9 s.
Use first equation of motion for rotational motion
ω = ωo + αt
ω = 0 + 30.5 x 9
ω = 274.5 rad/s
v = rω
v = 0.120 x 274.5
v = 32.94 m/s
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N
b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
You apparently haven't noticed yet . . .
The moon rises in the East, moves across the sky, and sets
in the West, just like the sun and everything else in the sky.
It takes the moon about 12 hours and 25 minutes to go from
rising to setting, and then it rises again about 24 hours and
49 minutes later. So each day, the moon rises about 49 minutes
later than it rose on the previous day.
In order to describe the direction and height of the moon in the sky,
you need to tell the date and the time, and also the latitude on Earth
from which you observed it. And wherever the moon was in the sky
at that time, it was in a noticeably different place 30 minutes later.
Just like the sun.