Answer:
You not alone lolI'm also tryna figure out the answer
Answer:
The answer is
<h3>3.75 × 10²⁴ atoms of Al</h3>
Explanation:
To find the number of atoms of Al given it's number of moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
n = 6.23 mol
We have
N = 6.23 × 6.02 × 10²³
We have the final answer as
<h3>3.75 × 10²⁴ atoms of Al</h3>
Hope this helps you
This is an incomplete question, here is a complete question.
Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.
Answer : The volume of iron(II) bromide solution is, 
Explanation : Given,
Concentration of iron(II) bromide = 1.29 mo/L
Moles of iron(II) bromide = 275 mmol = 0.275 mol
conversion used : 1 mmol = 0.001 mol
Now we have to calculate the volume of iron(II) bromide.

Now put all the given values in this formula, we get:

Thus, the volume of iron(II) bromide solution is, 
Answer:
In chemistry, valence electrons are the electrons that are located in the outermost electron shell of an element.
Explanation: