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Nataly [62]
3 years ago
6

What’s the role of moles in weathering??????? HURRY ASAP HURRY PLEASE⁉️⁉️⁉️

Physics
2 answers:
Arturiano [62]3 years ago
8 0

Borrowing animals, such as moles, dig holes that expose new rocks to the effects of weathering. The holes then allow water and other weathering agents to reach the rock layer that had been covered by the soil.

babymother [125]3 years ago
4 0

What do you mean? What step of weathering? They help process dead organisms, and transfer soil.

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noname [10]

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Explanation:

4 0
3 years ago
If the speed is c=3.00•80 m/s and the frequency is 1030kHz=1030•30 Hz what’s the wavelength
Nana76 [90]

Answer:0.3meters

Explanation:

wavelength=velocity ➗ frequency

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2 years ago
Cruise control should not be used _____.
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3 years ago
La velocidad de un tren se reduce uniformemente de 12m/s a 5m/s. Sabiendo que durante ese tiempo recorre una distancia de 100 m.
KATRIN_1 [288]

Responder:

Explicación:

Dados los siguientes datos

Valor inicial u = 12 m / s

velocidad final v = 5 m / s

Distancia S = 100 m

Necesario

aceleración del tren.

Usando la ecuación de movimiento

v² = u² + 2as

2as = v²-u²

a = v²-u² / 2s

Sustituyendo los valores dados para obtener la aceleración que tenemos;

a = 5²-12² / 2 (100)

a = 25-144 / 200

a = -119/200

a = -0,595 m / s²

Por tanto, la aceleración del tren durante este período es de -0,595 m / s²

b) Si el tren viaja a una parada desde 5 m / s, su velocidad final será cero y su velocidad inicial u será 5 m / s

Para obtener la distancia durante este período, sustituiremos u = 5 m / s, v = 0 m / sy a = -1,19 m / s² en la ecuación de movimiento anterior;

v² = u² + 2as

0² = 5²-2 (0.595) s

0 = 25-1,19 s

1,19 s = 25

s = 25 / 1,19

Responder:

Explicación:

Dados los siguientes datos

Valor inicial u = 12 m / s

velocidad final v = 5 m / s

Distancia S = 100 m

Necesario

aceleración del tren.

Usando la ecuación de movimiento

v² = u² + 2as

2as = v²-u²

a = v²-u² / 2s

Sustituyendo los valores dados para obtener la aceleración que tenemos;

a = 5²-12² / 2 (100)

a = 25-144 / 200

a = -119/200

a = -0,595 m / s²

Por tanto, la aceleración del tren durante este período es de -0,595 m / s²

b) Si el tren viaja a una parada desde 5 m / s, su velocidad final será cero y su velocidad inicial u será 5 m / s

Para obtener la distancia durante este período, sustituiremos u = 5 m / s, v = 0 m / sy a = -1,19 m / s² en la ecuación de movimiento anterior;

v² = u² + 2as

0² = 5²-2 (0.595) s

0 = 25-1,19 s

1,19 s = 25

s = 25 / 1,19

s = 21,0 m

Por lo tanto, la distancia que recorre hasta detenerse asumiendo la misma aceleración es 21.0 m

3 0
2 years ago
What happens to parallel light rays that strike a concave lens?
Fiesta28 [93]
When parallel light rays comes across a concave lens, the rays are refracted outwards. Concave lenses are thinner in the middle part. Parallel light rays diverge and seems to appear from one point called the principal focus. The image formed is smaller. 
6 0
3 years ago
Read 2 more answers
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