The time the package travels horizontally is equal to the time it takes to hit the ground. This can be calculated using:
s = ut + 1/2 at²; u is 0
480 = 4.9t²
t = 9.90 seconds

Horizontal distance = horizontal speed x time
The speed will be converted to m/s from km/h
= 180 km/hr x 1000m/km x 1hr/3600 seconds x 9.90 seconds
= 495 m

5 0

2 years ago

A hot plume of mantle material, which may extend to the core-mantle boundary, produces a volcanic region a few hundred kilometer

Fantom [35]

Answer: Hot spot

The volcanic hot spot is an area in the mantle from which heat rises as a thermal plume from deep in the Earth.

5 0

2 years ago

Read 2 more answers

Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d

alex41 [277]

Answer:

$v=18.89\frac{m}{s}$

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

$\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)$

Solving N from (2) and replacing in (1):

$N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c$

The centripetal acceleration is given by:

$a_c=\frac{v^2}{r}$

Replacing and solving for v:

$gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}$

4 0

3 years ago

When is an object that has been dropped from a great height through the air closest to vein in a free fall?

Elza [17]

-- "Free fall" means no forces acting on the object except for gravity.

-- An object dropped through air has two forces on it -- gravity and air resistance.

-- So we're looking for the part of the drop where air resistance is smallest.

-- The force of air resistance depends on the speed through the air, so the
force of air resistance is smallest when <em>velocity downward is smallest</em>.

7 0

3 years ago

Read 2 more answers