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Fed [463]
2 years ago
11

Find the volume of a sphere having a radius of 9/8mi

Mathematics
1 answer:
Tamiku [17]2 years ago
3 0

\piAnswer:

the volume is 5.96

Step-by-step explanation:

v =\frac{4}{3} \pi r^3\\\\

9/8 as a decimal is 1.13

\frac{4}{3}×\pi×1.13³≈5.96412

Hope this helps:).......if not then sorry for wasting your time and may God bless you:)

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Yakvenalex [24]
The lesser of the numbers given are -16 because -16 is more negative.
3 0
3 years ago
Read 2 more answers
I need help with this somebody help
Mariulka [41]

Answer:

Width: x + 3

(Length, width):

(5,4) (6,5) (7,6)

Step-by-step explanation:

x² + 7x + 12

x² + 4x + 3x + 12

x(x + 4) + 3(x + 4)

(x + 4)(x + 3)

Longer one is the length,

With is (x + 3)

x = 1,

5 × 4

x = 2,

6 × 5

x = 3,

7 × 6

3 0
3 years ago
Find the area of the region that lies inside the first curve and outside the second curve.
marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the  the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = \dfrac{1}{2}

\theta = -\dfrac{\pi}{3}, \ \  \dfrac{\pi}{3}

Now, the area of the  region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \  \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \  5^2 d \theta

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \  \theta  d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \   d \theta

A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  \dfrac{cos \ 2 \theta +1}{2}  \end {pmatrix} \ \ d \theta - \dfrac{25}{2}  \begin {bmatrix} \theta   \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}

A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  {cos \ 2 \theta +1}  \end {pmatrix} \ \    d \theta - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}}    \ \ - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{2 \pi}{3} \end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3})  \end {bmatrix} - \dfrac{25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} +   \dfrac{\pi}{3}  \end {bmatrix}- \dfrac{ 25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3}   \end {bmatrix}- \dfrac{ 25 \pi}{3}

A =    \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx
7 0
3 years ago
Nine different numbers between 10 and 200 that have a sum of their digits equal.to 6
Lady bird [3.3K]
One answer (of several) would be 33:  It's between 10 and 200 and the sum of its digits is 6.  Continue this same pattern to identify other answers.
8 0
3 years ago
Find the x and y intercepts of the graph of the function
Mkey [24]

Answer:

y intercepts= 0       x intercepts= none

nation:

The 2 funtions above the x axis do not intercept with the y-axis or the x-axis. They just hover above it, but never atcually touch it.

The function bellow the x-axis only intercepts the y-axis at 0,0

8 0
2 years ago
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