If a number has a decimal that is .5+, you round up. If it is .4-, you round down. So 817.502 would be 818.
let's recall that a cube is just a rectangular prism with all equal sides, check picture below.
![\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5C%20V%3Ds%5E3~~%20%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20V%3D%2627000%20%5Cend%7Bcases%7D%5Cimplies%2027000%3Ds%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B27000%7D%3Ds%5Cimplies%2030%3Ds%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bsurface%20area%20of%20a%20cube%7D%5C%5C%5C%5C%20SA%3D6s~~%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20s%3D%2630%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D6%2830%29%5Cimplies%20SA%3D180)
The appropriate measure of central tendency is one that shows
difference and is suitable for a scale that is nominal.
Response:
- The measure of central tendency to use is the <u>mode</u>.
<h3>How can the appropriate measure of central tendency be selected?</h3>
The mean is the sum of the measurements divided by the number count
of the plants.
The mode is the measurement that has the highest frequency.
The median is the measurement of the middle plant when arranged in a
given order according to size.
To argue that there is a difference between the plants, the measure of
central tendency to use is the mode, given that the data involves
measurements which can be expressed in a nominal scale.
Therefore;
- The measure of central tendency that will be best for Mrs. Hull to use is the<u> mode</u>
Learn more about the measures of central tendencies here:
brainly.com/question/1027437
Answer:
100 Rs 5 coins and 50 Rs 2 coins
Step-by-step explanation:
Bhairav collected Rs.600 in his piggy bank by putting in Rs.2 and Rs.5 coins. The number of Rs.5 coins are twice as many as Rs.2 coins
Let x be the number of 5 coins
and y be the number of 2 coins
The number of Rs.5 coins are twice as many as Rs.2 coins
Replace x with 2y
So 100 Rs 5 coins and 50 Rs 2 coins
