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LuckyWell [14K]
2 years ago
13

What is energy converted to if it is not used to do work?

Physics
1 answer:
Romashka [77]2 years ago
3 0

Answer:

the human body isn't very efficient at converting food into useful work. The human body is less than 5% efficient most of the time. The rest of the energy is converted to heat, which may or may not be useful, depending on how cool or warm a person wants to be.

Explanation:

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Which is one<br> step that geologists use to find the epicenter of an earthquake?
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Answer:

triangulation

Explanation:

using your compass

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An experiment discovered that a particular material was a poor conductor of electricity. This material would most likely be used
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What is a device that does not work with an electric circuit?
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It would be a bike that doesn't use an electric circuit.
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3 years ago
The blades of a fan running at low speed turn at 250 rpm. When the fan is switched to high speed, the rotation rate increases un
fgiga [73]

Answer:

1.82 rad/s².

Explanation:

Applying,

α = (ω₂-ω₁)/t..................... Equation 1

Where α = angular acceleration of the fan blades, ω₂ = final angular velocity of the fan blades, ω₁ = initial angular velocity of the fan blades, t =  time.

Given: ω₂ = 350 rpm = (350×0.1047) rad/s = 36.645 rad/s. ω₁ = 250 rpm = (250×0.1047) rad/s = 26.175 rad/s, t = 5.75 s.

Substitute into equation 1

α = (36.645-26.175)/5.75

α = 10.47/5.75

α = 1.82 rad/s².

Hence the magnitude of the angular acceleration of the fan blades = 1.82 rad/s²

8 0
3 years ago
A 2.2 m long simple pendulum oscillates with a period of 4.8 s on the surface of unknown planet. What is the surface gravity of
Vsevolod [243]

Answer:

g=3.76\ m/s^2

Explanation:

Given that,

The length of a simple pendulum, l = 2.2 m

The time period of oscillations, T = 4.8 s

We need to find the surface gravity of the planet. The time period of the planet is given by the relation as follows :

T=2\pi \sqrt{\dfrac{l}{g}} \\\\T^2=4\pi ^2\times \dfrac{l}{g}\\\\g=\dfrac{4\pi ^2 l}{T^2}

Put all the values,

g=\dfrac{4\pi ^2 \times 2.2}{(4.8)^2}\\\\=3.76\ m/s^2

So, the value of the surface gravity of the planet is equal to 3.76\ m/s^2.

7 0
3 years ago
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