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Oduvanchick [21]
3 years ago
10

Which ball has the greater average speed during the 1-s interval after release (assuming neither hits the ground during that tim

e)? View Available Hint(s) Which ball has the greater average speed during the 1-s interval after release (assuming neither hits the ground during that time)? the ball thrown upward the ball thrown downward Neither; the average speeds of both balls are the same.
Physics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

The ball thrown downward

Explanation:

When the ball is thrown vertically, the acceleration of it is the gravity acceleration independent if it is thrown downward or upward. However, the acceleration is a vector, so, when the ball is thrown upward, the movement is against the gravity, so the acceleration is negative, and so, the velocity decreases during time; and when the ball is thrown downward, the movement goes to the gravity, so the acceleration is positive, so the velocity increase after time passes.

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The flaming gorge bridge, in wyoming rises above a dry gulch. If you throw a rock straight out from the bridge, horizontally, an
Novosadov [1.4K]

Answer:

12.495m/s

Explanation:

Horizontal displacement is the range of the projectile motion.

The range is expressed as;

R = 2U/g

U is the speed at which the rock is thrown (initial speed)

g is the acceleration due to gravity.

Given

R = 255cm = 2.55m

g = 9.8m/s²

Required

Speed U

Substitute the given parameters into the formula as shown;

2.55 = 2U/9.8

Cross multiply

2U = 2.55×9.8

2U = 24.99

U = 24.99/2

U = 12.495m/s

Hence the speed that you thew the rock is 12.495m/s

7 0
2 years ago
Use your calculator to evaluate -3.7 meter/second-13.9 meter/second 21.4 second-72 second
cluponka [151]

Answer :

(-3.7 meter/second) - (13.9 meter/second) = -17.6 meter/second

(21.4 second) - (72 second) = -50.6 second

Explanation :

(1) As we are given the expression :

(-3.7 meter/second) - (13.9 meter/second)

Now we have to evaluate this expression, we get:

⇒ -17.6 meter/second

(2) As we are given the expression :

(21.4 second) - (72 second)

Now we have to evaluate this expression, we get:

⇒ -50.6 second

6 0
2 years ago
When the starter motor on a car is engaged, there is a 290 A current in the wires between the battery and the motor. Suppose the
Tema [17]

Answer:

33.6\times10^{-4}}\text{ m} = 3.36 mm

Explanation:

From Ohm's law,

V = IR (Voltage = Current * Resistance)

R = \dfrac{V}{I}

The geometric definition of resistance is

R = \rho\dfrac{l}{A}

where \rho is the resistivity of the material, l  and A are the length and cross-sectional area, respectively.

A = \rho\dfrac{l}{R}

A = \rho\dfrac{l\timesI}{V}

Since the wire is assumed to have a circular cross-section, its area is given by

A = \pi\dfrac{d^2}{4} where d is the diameter.

\pi\dfrac{d^2}{4} = \rho\dfrac{l\timesI}{V}

d = \sqrt{\dfrac{4\rho l I}{\pi\times V}}

Resistivity of copper = 1.68\times10^{-8}. With these and other given values,

d = \sqrt{\dfrac{4\times1.68\times10^{-8}\times1.5\times290}{3.14\times 0.55}}

d = \sqrt{1128.43\times10^{-8}}

d = 33.6\times10^{-4} \text{ m}

5 0
3 years ago
The potential-energy function u(x) is zero in the interval 0≤x≤l and has the constant value u0 everywhere outside this interval.
VMariaS [17]
Look first for the relation between deBroglie wavelength (λ) and kinetic energy (K): 
K = ½mv² 
v = √(2K/m) 
λ = h/(mv) 
= h/(m√(2K/m)) 
= h/√(2Km) 

So λ is proportional to 1/√K. 
in the potential well the potential energy is zero, so completely the electron's energy is in the shape of kinetic energy: 
K = 6U₀ 

Outer the potential well the potential energy is U₀, so 
K = 5U₀ 
(because kinetic and potential energies add up to 6U₀) 

Therefore, the ratio of the de Broglie wavelength of the electron in the region x>L (outside the well) to the wavelength for 0<x<L (inside the well) is: 
1/√(5U₀) : 1/√(6U₀) 
= √6 : √5
5 0
3 years ago
You have a piece of cork with a volume of 2 cm^3 and a density of 210kg/m^3. You hold it under water and release it.
insens350 [35]

I am sorry if it didn't helped

answers;

Calculate the buoyant force of a piece of cork of 8cm3 that floats in water. Density of cork is 207kg/m3. ?

I need the mass, in order to get the volume to apply t to the Buoyancy formula of: B=(W)object=(m)object(g)

Explanation:

From Archimedes Principle, any object partially or totally submerged in a fluid is buoyed upwards with a force equal to the weight of the displaced fluid.

∴

B

=

ρ

f

l

V

f

l

g

=

1000

k

g

/

m

3

×

8

×

10

−

6

m

3

×

9

,

8

m

/

s

2

=

0

,

0784

N

(assuming the density of water is at standard temperature and pressure, and that the cork is totally submerged as it floats in the water

it's not the answer of your question ⁉️ but it is similar ........

7 0
2 years ago
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