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3 years ago

14

Instantaneous speed is measured

1 answer:

juin [17]3 years ago

4 0

The correct answer is C

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What are the different isotopes

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Isotopes can both be the same element but have a different number of electrons

Explanation: not sure if more was supposed to be there, but i tried

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3 years ago

Describe the advantages and disadvantages of keeping the road clear of ice

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3 years ago

Astronauts think planets formed from interstellar dust and gases that clumped together in a process called _

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3 years ago

Based on the data in the table...especially the provided melting points, which two substances are

ArbitrLikvidat [17]

The two substances that are mostly likely examples of covalent bonding are Sucrose and Ethanol.

<h3 /><h3 /><h3>What is a covalent Bond?</h3>

A covalent bond is a type of chemical bond that involves the sharing of pairs of electron between atoms.

Examples of compounds with covalent bond include the following;

Distilled water
Sucrose
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Olive oil is a mixture not a compound

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Learn more about covalent bonds here: brainly.com/question/12732708

7 0

2 years ago

A counterflow double-pipe heat exchanger is used to heat water from 20°C to 80°C at a rate of 1.2 kg/s. The heating is to be com

bixtya [17]

Answer:L=109.16 m

Explanation:

Given

initial temperature $=20^{\circ}C$

Final Temperature $=80^{\circ}C$

mass flow rate of cold fluid $\dot{m_c}=1.2 kg/s$

Initial Geothermal water temperature $T_h_i=160^{\circ}C$

Let final Temperature be T

mass flow rate of geothermal water $\dot{m_h}=2 kg/s$

diameter of inner wall $d_i=1.5 cm$

$U_{overall}=640 W/m^2K$

specific heat of water $c=4.18 kJ/kg-K$

balancing energy

Heat lost by hot fluid=heat gained by cold Fluid

$\dot{m_c}c(T_h_i-T_h_e)= \dot{m_h}c(80-20)$

$2\times (160-T)=1.2\times (80-20)$

$160-T=36$

$T=124^{\circ}C$

As heat exchanger is counter flow therefore

$\Delta T_1=160-80=80^{\circ}C$

$\Delta T_2=124-20=104^{\circ}C$

$LMTD=\frac{\Delta T_1-\Delta T_2}{\ln (\frac{\Delta T_1}{\Delta T_2})}$

$LMTD=\frac{80-104}{\ln \frac{80}{104}}$

$LMTD=91.49^{\circ}C$

heat lost or gain by Fluid is equal to heat transfer in the heat exchanger

$\dot{m_c}c(80-20)=U\cdot A\cdot$ (LMTD)

$A=\frac{1.2\times 4.184\times 1000\times 60}{640\times 91.49}=5.144 m^2$

$A=\pi DL=5.144$

$L=\frac{5.144}{\pi \times 0.015}$

$L=109.16 m$

6 0

3 years ago