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Eva8 [605]
3 years ago
12

PLEASE HELP ME I WILL LOVE U FOREVER

Chemistry
1 answer:
AlekseyPX3 years ago
7 0

Answer:

according to me option a is the correct one

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Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur:
Gekata [30.6K]
<span>AX(aq)+BY(aq)→no precipitate
AX(aq)+BZ(aq)→precipitate
this two equations imply
</span>
AX(aq) is soluble and <span>BY(aq) is insoluble

the answer is
</span><span>E. BY</span>
5 0
4 years ago
A buffer consists of 0.45 M CH3COOH (acetic acid) and 0.35 M CH3COONa. The Ka of acetic acid is 1.8 x 10-5 . a) Calculate the pH
Zigmanuir [339]

Answer:

A) pH of Buffer solution = 4.59

B) pH after 5.0 ml of 2.0 M NaOH have been added to 400 ml of the original    buffer solution = 4.65

Explanation:

This  is the Henderson-Hasselbalch Equation:

 pH = pKa + log\frac{[conjugate base]}{[acid]}

to calculate the pH of the following Buffer solutions.

8 0
4 years ago
Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of
dsp73
The first thing we need to do here is to recognize the unit of molarity and the units of the given percentage of nitric acid.

Molarity is mol HNO3 / L of solution. This is our aim

The given percentage is 0.68 g HNO3/ g solution

multiplying this with density to convert g solution into mL solution and dividing with the molecular weight of HNO3 (63 g/mol) to convert g HNO3 to mol. Therefore we obtain

0.016 mol/ mL or 16.23 mol/ L (M)

6 0
3 years ago
What is the wavelength of a 2500 kg truck traveling at a rate of 75km/h?
Pepsi [2]

m = mass of the truck traveling = 2500 kg

v = speed of the truck traveling = 75 km/h = 75 (km/h) (1000 m/ 1 km) (1 h /3600 sec) = 20.83 m/s

h = plank's constant = 6.63 x 10⁻³⁴

λ = wavelength of truck = ?

according to de broglie's principle, wavelength of truck is given as

λ = h/(mv)

inserting the values in the above equation

λ = (6.63 x 10⁻³⁴)/((2500) (20.83))

λ = 1.3 x 10⁻³⁸ m

5 0
3 years ago
Read 2 more answers
What volume is occupied by 0.102 molmol of helium gas at a pressure of 0.95 atmatm and a temperature of 305 kk ?
zalisa [80]

The volume occupied by 0.102 mole of the helium gas is 2.69 L

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Number of mole (n) = 0.102 moles
  • Pressure (P) = 0.95 atm
  • Temperature (T) = 305 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Volume (V) =?

<h3>How to determine the volume </h3>

The volume of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both sides by P

V = nRT / P

V = (0.102 × 0.0821 × 305) / 0.95

V = 2.69 L

Thus, the volume of the gas is 2.69 L

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

8 0
1 year ago
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