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qwelly [4]
2 years ago
14

The smallest unit that can exist as an element and still have the properties of that element is a(n):

Chemistry
2 answers:
Yuri [45]2 years ago
8 0
The smallest unit that can exist as an element and still have proprieties of that element is an Atom<span />
liq [111]2 years ago
6 0

Explanation:

Every element is made up of atoms which cannot be further divided into simpler substances.

For example, a piece of zinc metal will only contains atoms of zinc and no there element.

Since, these atoms are the same as the element itself. Hence, the element still retain its properties because there no other different element is present in it.

Thus, we can conclude that the smallest unit that can exist as an element and still have the properties of that element is an atom.

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3 0
3 years ago
In the Minnesota Department of Health set a health risk limit for acetone in groundwater of 60.0 μg/L . Suppose an analytical ch
siniylev [52]

Answer:

m = 4.7 μg

Explanation:

Given data:

density of acetone = 60.0  μg/L

Volume = 79.0 mL

Mass = ?

Solution:

Formula:

d = m/v

v = 79.0 mL × 1L /1000 mL

v = 0.079 L

Now we will put the values on formula:

d = m/v

60.0  μg/L = m/0.079 L

m = 60.0 μg/L × 0.079 L

m = 4.7 μg

So health risk limit for acetone = 4.7  μg

3 0
2 years ago
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Ludmilka [50]

Answer:

NEEE

Explanation:

5 0
3 years ago
How to do Criss cross method of lithium carbide?
timama [110]
You will need to go on yt
5 0
2 years ago
1.
Leya [2.2K]

Answer:

V₂ = 530.5 mL

Explanation:

Given data:

Initial temperature = 20.0°C

Final temperature = 40.0 °C

Final volume = 585 mL

Initial volume = ?

Solution:

Initial temperature = 20.0°C (20+273 = 293 K)

Final temperature = 40.0 °C (40+273 = 323 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂  

V₂ = 585 mL × 293 K / 323 K

V₂ = 171405 mL.K / 323 K

V₂ = 530.5 mL

6 0
2 years ago
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