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3 years ago

The smallest unit that can exist as an element and still have the properties of that element is a(n):

Chemistry

2 answers:

Yuri [45]3 years ago

8 0

The smallest unit that can exist as an element and still have proprieties of that element is an Atom

liq [111]3 years ago

6 0

Explanation:

Every element is made up of atoms which cannot be further divided into simpler substances.

For example, a piece of zinc metal will only contains atoms of zinc and no there element.

Since, these atoms are the same as the element itself. Hence, the element still retain its properties because there no other different element is present in it.

Thus, we can conclude that the smallest unit that can exist as an element and still have the properties of that element is an atom.

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3 years ago

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3 years ago

Calculate the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remain

Reil [10]

The balanced chemical equation for the production of chromium metal from the reaction of chromium(ll) nitrate reacts with a strip of zinc is:

3 Zn + 2 Cr(NO₃)₃ → 2 Cr + 3 Zn(NO₃)₂

This is a redox reaction, which is a chemical reaction in which one or more electrons are transferred between the reagents, causing a change in their oxidation states. In the proposed reaction, Cr oxidation state goes from +3 to 0, becoming metallic chromium, while Zn goes from being Zn⁰ to Zn²⁺.

The mass of chromium metal produced in the above reaction will be,

425.0 mL x $\frac{1 L}{1000 mL}$ x $\frac{0.25 mol Cr(NO_{3})_{3} }{1 L}$ x $\frac{2 mol Cr }{2 mol Cr(NO_{3})_{3} }$ x $\frac{51.9961 g Cr}{1 mol Cr}$ = 5.52 g

So, the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remains in excess is 5.52 g of Cr.

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3 years ago

How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work use

Lera25 [3.4K]

1) Find the number of moles that the final solution must contain

M = n / liters of solution => n = M*liters of solution

n = 1.5 mol/liter * 25.0 liter = 37.5 moles

2) Find how many liters of the stock solution contain 37.5 moles of HCL

M = n / liters of sulution => liters of solution = n / M = 37.5 mol / 18.5 mol/liter

liter of solution = 2.03 liter

Answer: 2.03 liter

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3 years ago