Fluorine (F) will have properties similar to Bromine (Br) because it belongs to the same group as Bromine.
Answer:
3.73 mL
Explanation:
To solve this problem we can use the equation C₁V₁=C₂V₂, where:
We<u> input the data</u>:
- 6.57 M * V₁ = 0.0490 M * 500 mL
And <u><em>solve for V₁</em></u>:
So 3.73 mL of a 6.57 M stock solution would be required to prepare 500 mL of a 0.0490 M solution.
Partial negative charge is transferred to more electronegative and this it creates the bond polar.
If we assume this two gases behave like ideal gas, then we use the ideal gas law
, where P is the pressure, V is the volume, n number of moles, R gas constant and T the temperature in kelvins. As well as the density formula
. First we calculate the molarity for Freon
.
The number of moles for freon are

We know
, so we insert this concept to our ideal gas equation
. Since
, we insert this concept to the formula
. The measurements take place in same conditions so,
