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seropon [69]
2 years ago
5

Which is an example of a compound? 1. Gold 2. Iodine 3. Water 4. Sand

Chemistry
1 answer:
nirvana33 [79]2 years ago
5 0

Water

Explanation: A compound can be defined as the bonding of two or more atoms, where at least two are different types of atoms. That is, they are atoms from more than one element. Water fits this definition as it is the bonding between two hydrogen atoms and one oxygen atom, with chemical formula H2O. Iodine and gold are elements and therefore are only single atoms. Sand is classified as a mixture and therefore is not the correct option.

Mark it brainliest if im correct :)

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What mass (in grams) of Mg(NO3)2 is present in 151 mL of a 0.350 M solution of Mg(NO3)2?
Mademuasel [1]

Answer is: A) 7.84 g.

V(Mg(NO₃)₂) = 151 mL ÷ 1000 mL/L.

V(Mg(NO₃)₂) = 0.151 L; volume of the magnesium nitrate.

c(Mg(NO₃)₂) = 0.352 M; molarity of the solution.

n(Mg(NO₃)₂) = V(Mg(NO₃)₂) · c(Mg(NO₃)₂).

n(Mg(NO₃)₂) ) = 0.151 L · 0.352 mol/L.

n(Mg(NO₃)₂) = 0.0531 mol; amount of the substance.

M(Mg(NO₃)₂) = Ar(Mg) + 2Ar(N) + 6Ar(O) · g/mol.

M(Mg(NO₃)₂) = 24.3 + 2·14 + 6·16 · g/mol.

M(Mg(NO₃)₂) = 148.3 g/mol; molar mass.

m(Mg(NO₃)₂) = n(Mg(NO₃)₂) · M(Mg(NO₃)₂).

m(Mg(NO₃)₂) = 0.0531 mol · 148.3 g/mol.

m(Mg(NO₃)₂) = 7.84; mass of magnesium nitrate.

6 0
3 years ago
Read 2 more answers
According to the following reaction, what volume in milliliters of 0.244M KCl(aq) solution is required to react exactly with 50.
Elodia [21]

Answer:

There is 86.1 mL of KCl needed

Explanation:

<u>Step 1:</u> Data given

Molarity of KCl = 0.244 M

Volume of a 0.210 M Pb(NO3)2 = 50.0 mL = 0.05 L

<u>Step 2:</u> The balanced equation

2KCl(aq) + Pb(NO3)2(aq) -> PbCl2(s) + 2KNO3(aq)

<u>Step 3:</u> Calculate moles Pb(NO3)2

moles Pb(NO3)2 =molarity * volume

moles Pb(NO3)2 = 0.210 M * 0.05 L

moles Pb(NO3)2 = 0.0105 moles

<u>Step 4:</u> Calculate moles of KCl

For 1 mole of Pb(NO3)2 we need 2 moles of KCl

moles KCl required = 0.0105 * 2 =0.0210  moles

<u>Step 5:</u> Calculate volume of KCl

Volume = moles KCl / molarity KCl

V = 0.0210 moles / 0.244 M=0.0861 L = 86.1 mL

There is 86.1 mL of KCl needed

6 0
3 years ago
Can a liquid be measured in millimeters and kilometers
Ivanshal [37]
Milliliter and killoliter! So no u can't measure a liquid with meters
8 0
3 years ago
Read 2 more answers
If i initially have 4.0 l of a gas at a pressure of 1.1 atm, what will the volume be if i increase the pressure of 3.4 atm?
ddd [48]
  The  volume  of  a  gas  that   its  pressure  increase  to  3.4  atm   is    calculated  as   follows

  By  use  of  boyles   law   that  is  P1V1=P2V2
V1=4.0  L
P1=1.1  atm
P2=3.4  atm
V2= P1V1/P2  

(1.1  atm  x  4.0 L)/3.4  atm=  1.29  L
4 0
2 years ago
What describes a mixture
kirill [66]

Answer:

a mixture is a material made up of two or more different substances which are physically combined.

4 0
3 years ago
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