When doing perimeter and area do you add or multiply
2 answers:
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Answer:
Magnitude of the resulting force on the 7 nC charge at the origin:
Fn₁= 23.95*10⁻⁹ N
Explanation:
Look at the attached graphic:
Charges of positive signs exert repulsive forces on q₁ + and charges of negative signs exert attractive forces on q₁ +.
q₁ experiences three forces (F₂₁,F₃₁,F₄₁) and we calculate them with Coulomb's law:
F = (k*q₁*q)/(d)²
m : distance from q₁ to q₂
(d₁₂)² = 18 m²
m : distance from q₁ to q₃
(d₁₃)² = 10 m²
m : distance from q₁ to q₄
(d₁₄)² = 13 m²
K= 8.98755 × 10⁹ N *m²/C²
q₁= 7*10⁻⁹C
k*q₁=8.98755*10⁹ *7*10⁻⁹= 62.9
F₂₁= (62.9)*(9* 10⁻⁹) /(18) = 31.45*10⁻⁹ C
F₃₁= (62.9)*(7* 10⁻⁹) /(10) = 44*10⁻⁹ C
F₄₁= (62.9)*(8* 10⁻⁹) /(13) = 38.7*10⁻⁹ C
x-y components of the net force on q₁ (Fn₁):
α= tan⁻¹(3/3)= 45° , β= tan⁻¹(3/1)= 71.56° , θ= tan⁻¹(2/3)= 33.69°
Fn₁x = F₂₁x+ F₃₁x+F₄₁x
F₂₁x =+ F₂₁*cosα =+ (31.45*10⁻⁹)* (cos 45°) = +22.24 *10⁻⁹ N
F₃₁x= -F₃₁*cosβ = - ( 44*10⁻⁹)* (cos 71.56°) = -13.91 *10⁻⁹ N
F₄₁x= -F₄₁*cosθ = -(38.7*10⁻⁹)* (cos 33.69°) = -32.2*10⁻⁹ N
Fn₁x = (+22.24 - 13.91 - 32.2)*10⁻⁹ N
Fn₁x = -23.87 *10⁻⁹ N
Fn₁y = F₂₁y+ F₃₁y+F₄₁y
F₂₁x =+ F₂₁*sinα =+ (31.45*10⁻⁹)* (sin 45°) = +22.24 *10⁻⁹ N
F₃₁x= -F₃₁*sinβ = - ( 44*10⁻⁹)* (sin 71.56°) = -41.74 *10⁻⁹ N
F₄₁x= +F₄₁*sinθ = +(38.7*10⁻⁹)* (sin 33.69°) =+21.47*10⁻⁹ N
Fn₁y = (22.24 -41.74+21.47)*10⁻⁹ N
Fn₁y = 1.97*10⁻⁹ N
Magnitude of the resulting force on the 7 nC charge at the origin (q₁):
Fn₁= 23.95*10⁻⁹ N
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<u>Air pressure has no effect at all in an ideal gas approximation. This is because pressure and density both contribute to sound velocity equally, and in an ideal gas the two effects cancel out, leaving only the effect of temperature. Sound usually travels more slowly with greater altitude, due to reduced temperature.</u>
D) Partial charge cannot be removed, because charge is a discrete quantity that may exist only at certain values
Explanation:
The electric charge of an object is a property of the object that is related to the ability of the object to experience/exert an electric force: if the object is electrically charge, then it is attracted or repelled by other electrically charged object.
The electric charge of an object depends on the amount of charged particles it has on it. In particular, the fundamental particles that carry electric charge are:
- Protons: they carry electric charge of +e
- Electrons: they carry electric charge of -e
Where "e" is the fundamental charge (). Therefore, one proton carry a charge of +e and one electron carry a charge of -e.
An electron is a fundamental particle: this means that it cannot be divided into smaller particles. This also means that it is not possible to remove part of the charge of the electron: in fact, it is said that electric charge exists only as discrete values, being a multiple of . Therefore, the correct statement is
D) Partial charge cannot be removed, because charge is a discrete quantity that may exist only at certain values
Learn more about particles:
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