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gregori [183]
3 years ago
5

What quantity of heat is required to change 20g of ice at -25°c to steam at 120°c

Physics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer: 5289 joules

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since, Mass of ice = 20 g

C is not provided (Recall that the specific heat capacity of ice is 2.010J/g°C)

Φ = (Final temperature - Initial temperature)

(120°C - (-25°C) =

120°C + 25°C = 145°C

Thus, Q = 20g x 2.010J/g°C x 145°C

Q= 5829J

Thus, 5829Joules of heat energy is required to heat ice

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Hi im really confused:
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The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

U =  c_{p} m ΔT

U = Energy

c_{p} = Specific heat

m = Mass

ΔT = Change in temperature

ρ = Density

V = Volume

ρ = 1000 g / m³ (Dry air )

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ΔT = 5 °C

V = 4 * 4 * 3

V = 48 m³

m = ρ V

m = 1000 * 48

m = 48000 g

U = 1 * 48000 * 7

U = 336000 J

U = 336 kJ

Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

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It takes Seymour, a slimy slug, 20 minutes to travel from his favorite bush to the local trash can (a distance of 30 meters), ho
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Cohort studies allow the investigator to examine multiple outcomes and multiple exposures. Consider the following three exposure
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See the explanation for the answer.

Explanation:

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                      <u>Outcomes that were examined</u>

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2. Influence of outdoor air pollution in lung cancer

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4. Occupational factors and housing factor were observed.

                       

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Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is kilometers, and the
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Complete question is;

Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is 149,598,000 kilometers, and the eccentricity is 0.0167. Find the minimum distance (perihelion) and the maximum distance (aphelion) of Earth from the sun

Answer:

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Maximum distance = 152,096,286.6 km

Explanation:

The formula for the eccentricity of an ellipse is given by;

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a is distance from the center of ellipse to a vertex.

From the question, we are given;

a = 149,598,000

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Thus;

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Minimum distance = a - c

Minimum distance = 149598000 - 2498286.6

Thus;

Minimum distance = 147,099,713.4 km

Similarly, formula for the maximum distance (aphelion) is;

Max distance = a + c

Max distance = 149598000 + 2498286.6

Maximum distance = 152,096,286.6 km

4 0
3 years ago
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