Answer:
The distance between adjacent antinodes of the standing wave is 1.25 m.
Explanation:
Given that,
Frequency f= 120 MHz
We need to calculate the distance between adjacent antinodes of the standing wave
Using formula of distance
.....(I)
We know that,
![\lambda=\dfrac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bc%7D%7Bf%7D)
Put the value of
in to the equation (I)
![\Delta x=\dfrac{c}{2f}](https://tex.z-dn.net/?f=%5CDelta%20x%3D%5Cdfrac%7Bc%7D%7B2f%7D)
Where, c = speed of light
f = frequency
Put the all value into the formula
![\Delta x=\dfrac{3\times10^{8}}{2\times120\times10^{6}}](https://tex.z-dn.net/?f=%5CDelta%20x%3D%5Cdfrac%7B3%5Ctimes10%5E%7B8%7D%7D%7B2%5Ctimes120%5Ctimes10%5E%7B6%7D%7D)
![\Delta x=1.25\ m](https://tex.z-dn.net/?f=%5CDelta%20x%3D1.25%5C%20m)
Hence, The distance between adjacent antinodes of the standing wave is 1.25 m.
Answer:
e. is definitely zero
Explanation:
Given that
At initial condition the speed of the pop cans is zero.
We know that linear momentum
P = Mass x velocity
P = m v
At initial condition v = 0
P= 0
If there is no any external force then the linear momentum of the system will be conserve.And given that ,consider the system isolated.
Therefore the answer is e.
Answer:
B
Explanation:
Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.
It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.
Answer:
The results of this experiment is that the vast majority of the particles were very little deviated,
Explanation:
Rutherford's experiment consisted of making alpha particles that are helium nucleus with two positive charges on a thin sheet of gold.
The results of this experiment is that the vast majority of the particles were very little deviated, which agrees that the charge and mass of the electrons is small, so their repulsion is very small
A few particles are strongly deviated and much less highly deviated almost
back off, this allowed us to suggest that the positive charge and mass was concentrated in a very small area of space, which I call nucleus