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hoa [83]
3 years ago
5

What does the symbol "E3" represent? ...?

Physics
2 answers:
LiRa [457]3 years ago
7 0
The symbol "E3" represents the energy of electrons in the third energy level.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
laila [671]3 years ago
4 0

Answer:

E₃ = energy in third energy level.

Explanation:

The energy of an electron is third orbit is given by :

E=-\dfrac{13.6Z^2}{n^2}

Where

Z is the atomic number

n is principal quantum number and n = 1,2,3....

i.e. the energy of an electron is inversely proportional to the principal quantum number.

E₁,E₂,E₃.......... shows the energy of an electron in first, second and third energy level respectively.

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Suppose you wish to construct a motor that produces a maximum torque whose magnitude is 1.7 × 10-2 N·m. The coil of the motor ha
Len [333]

Answer:

86 turns

Explanation:

Parameters given:

Magnetic torque, τ = 1.7 * 10^(-2) Nm

Area of coil, A = 9 * 10^(-4) m²

Current in coil, I = 1.1 A

Magnetic field, B = 0.2 T

The magnetic toque is given mathematically as:

τ = N * I * A * B

Where N = number of turns

To find the number of turns, we make N subject of formula:

N = τ/(I * A * B)

Therefore:

N = (1.7 * 10^(-2)) / (1.1 * 9 * 10^(-4) * 0.2)

N = 85.85 = 86 turns (whole number)

The number of turns must be 86.

3 0
3 years ago
Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
givi [52]

Answer:

its most definitely c. trust me

Explanation:

3 0
2 years ago
(a) What is the escape speed on a spherical asteroid whose radius is 545 km and whose gravitational acceleration at the surface
Keith_Richards [23]

Answer:

1777.92 m/s

Explanation:

R = Radius of asteroid = 545 km

M = Mass of planet

g = Acceleration due to gravity = 2.9 m/s²

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Acceleration due to gravity is given by

g=\dfrac{GM}{R^2}\\\Rightarrow M=\dfrac{gR^2}{G}

The expression of escape velocity is given by

v=\sqrt{\dfrac{2GM}{R}}\\\Rightarrow v=\sqrt{\dfrac{2G}{R}\dfrac{gR^2}{G}}\\\Rightarrow v=\sqrt{2gR}\\\Rightarrow v=\sqrt{2\times 2.9\times 545000}\\\Rightarrow v=1777.92\ m/s

The escape speed is 1777.92 m/s

3 0
3 years ago
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MAVERICK [17]
The correc answer is B.
7 0
3 years ago
One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force f is applied to the other end of th
Vlada [557]

For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

F\times L = mg \times \frac{L}{2}

here weight will act at mid point of door so its distance is half of the total distance where force is applied

here we know that

mg = 145 N

now we will have

F = \frac{mg}{2}

F = \frac{145}{2} = 72.5 N

so our applied force is 72.5 N

7 0
3 years ago
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