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4 years ago

What does the symbol "E3" represent? ...?

2 answers:

7 0

The symbol "E3" represents the energy of electrons in the third energy level.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

laila [671]4 years ago

4 0

Answer:

E₃ = energy in third energy level.

Explanation:

The energy of an electron is third orbit is given by :

$E=-\dfrac{13.6Z^2}{n^2}$

Where

Z is the atomic number

n is principal quantum number and n = 1,2,3....

i.e. the energy of an electron is inversely proportional to the principal quantum number.

E₁,E₂,E₃.......... shows the energy of an electron in first, second and third energy level respectively.

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Density of salty water as compared to the density of pure water is

sweet-ann [11.9K]

The answer of this question is (c) is always more

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3 years ago

How is it possible for two objects to have the same momentum but different velocities give an example

castortr0y [4]

Momentum is
p = mv, where m is the mass and v is the speed.
So, if two objects have the same momentum but different speeds, the must have different masses as well.
v1/v2 = m2/m1
The example is a car and a truck. Car has the mass 1000 kg and velocity 100 m/s, and truck has the mass 5000 kg and velocity 20 m/s. Use the formula above to determine is it true that they have the same momentum:
(100 m/s) / (20 m/s) = (5000 kg) / (1000 kg)
5 = 5
So, the example is correct.
Hope this helps! Good luck!

4 0

3 years ago

Which is the best reason a writer would use a unreliable narrator

avanturin [10]

Answer: Explanation:

Authors sometimes use an Unreliable Narrator to tell the story, a protagonist who can't be trusted to tell the events accurately. Either they are insane, evil, delusional, forgetful, or just plain wrong... whatever their reasons, the writer uses this technique to 'hook' the reader.

7 0

3 years ago

In chemistry, potential energy is usually considered to be the energy _____________.

Lunna [17]

Answer:

The answer is option D. Stored in the chemical bonds.

Hope it helps............

4 0

3 years ago

Eld a distance r1 from P. The second particle is then released. Determine its speed when it is a distance r2 from P. Let q = 3.1

zheka24 [161]

Answer:

$v_{f}=1721.1m/s$

Explanation:

Given data

q = 3.1 µC

m = 47 mg

r1 = 0.83 mm

r2 = 2.5 mm.

As we know that:

$dK=-dU\\(1/2)mv_{f}^{2}-(1/2)mv_{i}^{2}=-(\frac{kq^{2} }{r_{f}}-\frac{kq^{2} }{r_{i}} )\\ (1/2)*(47*10^{-6}kg )v_{f}^{2}-(1/2)*(47*10^{-6}kg)(0)=-[(\frac{(9*10^{9}(3.1*10^{-6})^{2} }{2.5*10^{-3}}-(\frac{(9*10^{9}(3.1*10^{-6})^{2} }{0.83*10^{-3}} )]\\2.35*10^{-5} v_{f}^{2}=69.61\\v_{f}=\sqrt{\frac{69.61}{2.35*10^{-5}} }\\v_{f}=1721.1m/s$

5 0

3 years ago